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3 years ago

The atmosphere is divided into different layers, each with a different function. The stratosphere contains the ozone (O3).

Engineering

1 answer:

tangare [24]3 years ago

5 0

Answer:

a) At about 15 to 35 km from the Earth

b) It helps to absorb most of the ultraviolet rays from the sun, that is otherwise too dangerous here on Earth.

c) The depletion of the ozone layer is due to free radical catalysts, like nitric oxide (NO), nitrous oxide (N2O), hydroxyl (OH), but majorly due to atomic chlorine (Cl), and atomic bromine (Br) finding their way up to the the ozone layer.

d) The refrigeration processes and the aerosol aligned industrial processes, are the major culprits.

Explanation:

a) The ozone layer is lies in the lower portion of the stratosphere, from an height of about 15 to 35 kilometers from the surface of the Earth.

b) The ozone layer contains a large portion of ozone, a molecule of oxygen containing three oxygen atom bonded together. This ozone is created at this level by the action of ultraviolet radiation on an ordinary oxygen molecule, splitting it into two oxygen atom. Each of this oxygen atom then proceed to combine with another ordinary oxygen molecule, to form an ozone molecule. The ozone at this layer absorbs a large portion of the ultraviolet radiation from the sun.

c) The depletion of the ozone layer is due to the presence of some radical, that are able to survive up to the level of the ozone layer. At this level, ultraviolet radiation causes these these radicals to dissociate to give free bromine and chlorine mostly. This chlorine and bromine molecules breaks down the ozone molecules.

d) The various industrial processes includes refrigeration, and the aerosol industries that majorly releases the chlorofluorocarbons (CFCs) and bromofluorocarbons, which are the main culprits of ozone depletion.

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An incremental encoder is rotating at 15 rpm. On the wheel there are 40 holes. How many degrees of rotation would 1 pulse be?

elena-s [515]

Answer:

1 pulse rotate = 9 degree

Explanation:

given data

incremental encoder rotating = 15 rpm

wheel holes = 40

solution

we get here first 1 revolution time

as 15 revolution take = 60 second

so 1 revolution take = $\frac{60}{15}$

1 revolution take = 4 seconds

and

40 pulse are there for 1 revolution

40 pulse for 360 degree

so 1 pulse rotate is = $\frac{360}{40}$

1 pulse rotate = 9 degree

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3 years ago

Which test element is used to apply test execution settings for the main business flow excluding Login and Log out 1) Run time c

Svet_ta [14]

Test element is used to apply test execution settings for the main business flow excluding Login and Log out is "Transaction controller"

<u>Explanation:</u>

Transaction controllers are a technoscientifically kind of controllers that produce an additional sample that measures the overall time is taken or response time to perform its nested samplers.

The Controller has two checkboxes,those are

1.Generate Parent Samples

2. Include term of the timer and pre-post processors in the produced sample - It is the time which involves all processing samples within the Transaction controller, not just the HTTP samples. In Case one sample is lost or crashed then the entire Transaction Controller will fail. In case anyone sample assertion is failed then the complete Transaction Controller will fail.

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4 years ago

Two forces, one of which double the other has resultant of 280N. if the direction of the large force is reversed and the remaini

White raven [17]

Answer:

point is 16 N.If their resultant is normal to the smaller force and has a magnitude of 8 N. Then two forces are.

4 0

4 years ago

Water enters a vertical jet with low velocity and a pressure of 350 kPa. What is the maximum height that the water can rise abov

Lapatulllka [165]

The maximum height that the water can rise above the jet is: 35 meters.

<h3>Maximum height that the water can rise above the jet</h3>

Given:

P = 350 kPa = 350000 Pa

We would use pressure(p) formula to determine the maximum height that the water can rises above the jet by solving for h (height).

Using this formula

Pressure(P) = P₀ + ρgh

Where;

P₀ represent Pressure at the fluid's surface

ρ represent Density of the fluid = 1000 kg/m³

g represent acceleration due to gravity = 10 m/s².

h represent height

Solving for h (height)

350000 = 0 + (1000 × 10 ×h)

350000 = 10000h

Divide both side by 10000h

h = 350000/10000

h = 35 meters

Therefore the maximum height that the water can rise above the jet is: 35 meters.

Learn more about maximum height here:brainly.com/question/28088812

#SPJ1

4 0

2 years ago

Liquid flows at steady state at a rate of 2 lb/s through a pump, which operates to raise the elevation of the liquid 100 ft from

Greeley [361]

Answer:

D) 1.04 Btu/s from the liquid to the surroundings.

Explanation:

Given that:

flow rate (m) = 2 lb/s

liquid specific enthalpy at the inlet ( $h_{1}=40.09$ Btu/lb)

liquid specific enthalpy at the exit ( $h_{2}=40.94$ Btu/lb)

initial elevation ( $z_1=0ft$ )

final elevation ( $z_2=100ft$ )

acceleration due to gravity (g) = 32.174 ft/s²

$W_{cv}$ = 3 Btu/s

The energy balance equation is given as:

$Q_{cv}-W{cv}+m[(h_1-h_2)+(\frac{V_1^2-V_2^2}{2})+g(z_1-z_2)]=0$

Since kinetic energy effects are negligible, the equation becomes:

$Q_{cv}-W{cv}+m[(h_1-h_2)+g(z_1-z_2)]=0$

Substituting values:

$Q_{cv}-(-3)+2[(40.09-40.94)+\frac{32.174(0-100)}{778*32.174} ]=0\\Q_{cv}+3+2[-0.85-0.1285 ]=0\\Q_{cv}+3+2(-0.9785)=0\\Q_{cv}+3-1.957=0\\Q_{cv}+1.04=0\\Q_{cv}=-1.04\\$

The heat transfer rate is 1.04 Btu/s from the liquid to the surroundings.

8 0

3 years ago