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scoundrel [369]
3 years ago
12

Assume a and b are non zero rational numbers and c is an irrational number. For each of the following expressions determine dete

rmine wether the result is irrational rational or both justify your answers?

Mathematics
1 answer:
rodikova [14]3 years ago
4 0

Part A is irrational, but Parts B and C are both rational.

We know that Part A is irrational because an irrational number added to a rational number is still irrational. Also, an irrational number multiplied by a rational number is still irrational.

With Part B, we have an irrational number in the square root of 7. However, it is then squared to give us 7. This leaves us with 7 times a^2 which is rational. Two rational numbers multiplied still give us a rational number.

Finally, Part C only involves adding and multiplying rational numbers. Since that can only yield rational numbers, it must be rational.

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Help as soon as possible please
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(3x + 5)° + (10x - 7)° = 180°

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Solve for n: c= 6n−5g /11t
qwelly [4]

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Step-by-step explanation:

You have the equation c=6n-\frac{5g}{11t}.

Then, to solve for the variable n from the equation you need:

Make the subtraction of the right side of the equation:

(As the denominators are 1 and 11t, the least common denominator is 11t)

c=\frac{(6n)(11t)-5g}{11t}\\\\c=\frac{66nt-5g}{11t}

Multiply  11t to both sides:

(11t)c=(\frac{66nt-5g}{11t})(11t)\\\\11tc=66nt-5g

Add 5g to both sides:

11tc+5g=66nt-5g+5g\\\\11tc+5g=66nt

And finally divide both sides by 66t:

\frac{11tc+5g}{66t}=\frac{66nt}{66t}\\\\\frac{11tc+5g}{66t}=n

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