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MAVERICK [17]
3 years ago
12

In the diagram below, de is parallel to xy. what is the value of y​

Mathematics
1 answer:
Setler79 [48]3 years ago
6 0
The answer to your problem is D:86
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Which table represents a linear function?
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I would go with the first one.

Step-by-step explanation:

The first one is the only one that increases by the same number. In other words, its slope is constant. A linear function has a constant slope. You can tell that it increases by 1/2 every time.

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Choose the solution set represented by the following graph.
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Jacob put hummingbird feeders in his garden. To make the food for his small feeder, he mixed sugar with warm water. He used the
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Step-by-step explanation:

The smaller feeder is sweeter as it has more sugar molecules per unit of water than the larger feeder.

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2 years ago
Which of the following points lies on the circle whose center is at the origin and whose radius is 13?
Alexxandr [17]

any point that is on the circle will  have a distance of "radius" units, namely 13 units, since the radius is just that.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{origin}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})}\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{12})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(-5-0)^2+(12-0)^2}\implies d=\sqrt{(-5)^2+12^2} \\\\\\ d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13

8 0
3 years ago
Which equations for the measures of the unknown
MAXImum [283]

Answer: Option B, Option C, Option E

Step-by-step explanation:

The options written correctly, are:

A)x = cos^{-1}(\frac{a}{c})\\\\B) x = sin^{-1}(\frac{c}{b})\\\\C)x = tan^{-1}(\frac{c}{a})\\\\D) y = sin^{-1}(\frac{a}{c})\\\\ E)y = cos^{-1}(\frac{c}{b})

For this exercise you need to use the following Inverse Trigonometric Functions:

1)\ sin^{-1}(x)\\\\2)\ cos^{-1}(x)\\\\3)\ tan^{-1}(x)\\\\

When  you have a Right triangle (a triangle that has an angle that measures 90 degrees) and you know that lenght of two sides, you can use the Inverse Trigonometric Functions to  find the measure of an angle \alpha:

 1)\alpha = sin^{-1}(\frac{opposite}{hypotenuse}) \\\\2)\ \alpha =cos^{-1}(\frac{adjacent}{hypotenuse})\\\\3)\ \alpha=tan^{-1}(\frac{opposite}{adjacent})

Therefore, the conclusion is that the angles "x" and "y" can be found with these equations:

x=sin^{-1}(\frac{c}{b})\\\\x= cos^{-1}(\frac{a}{b})\\\\x=tan^{-1}(\frac{c}{a})\\\\\\ y=sin^{-1}(\frac{a}{b})\\\\y=cos^{-1}(\frac{c}{b})\\\\y=tan^{-1}(\frac{a}{c})

5 0
3 years ago
Read 2 more answers
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