Bug P has moved to +12 in 4 seconds, so is moving +3 units in each second.
.. x = 3t
Bug N has moved to -8 in 4 seconds, so is moving -2 units in each second.
.. y = -2t
_____
"per" means "divided by" (and vice versa), so -8 units per 4 seconds means
.. (-8 units)/(4 seconds) = -2 units/second . . . . . . . . reduce the fraction
When you multiply this fraction by a number of seconds, you cancel the "seconds" and the result is some number of units. For example,
.. (-2 units/second)*(4 second) = -8 units·second/second = -8 units
That is, speed multiplied by time gives distance.
In the equations above, we understand that the "3" means "3 units/second", and the "t" means "t seconds". Then when you multiply, the resulting x means "x units". The measures are usually left off and the equations are understood to give correct results when the variables have appropriate measures.
Answer:
3
9
21
Step-by-step explanation:
For the first one use the law of total probability
B=A∩B+A'∩B
12=9+A∩B
A∩B= 3
For this one you should use demorgans law and the union formula
(A'∩B')=(AUB)'
AUB= A+B-A∩B
6+12-3=15
15'= 24-15 = 9
For this one use demorgans law again
(A'UB')=(A∩B)'
(A∩B)'= 24-A∩B= 24-3= 21
Answer:
Mean of the data set is one of the most commonly used measures of central tendency. Basically, it means the average value of the data set. For finding it, one doesn't have to arrange the data in order. All it takes is to add them all together and divide that by the number of the data. It can be mathematically written as:
(x1 + x2 + x3 + ..... + xn) / n
This obviously means that Ashrita did the best job in calculating the mean of this data set.
2 ln 8 + 2 ln y
The first thing we could do is use the distributive property and "take out" the 2.
After we do that, we get
2( ln 8 + ln y)
Here's a cool property of logarithms of any base.
log a + log b = log ab
Note: The bases of the logarithms must be the same for this to work.
Let's apply that property
2 (ln 8 + ln y)
= 2 ln 8y
That could be your answer. If you want to remove the 2, we can use the following property:
a log b = log (a^b)
2 ln (8y)
= ln (8y)^2
= ln (64y^2)
That could be another answer.
Have an awesome day! :)