Blu ! The formula is right THERE, IN the question. All you have to do is plug numbers into it.
The formula: Kinetic Energy = 1/2 m v²
' m ' is 2,000 kg
' v ' is 22 m/s
Now pluggum in:
KE = (1/2) (2,000 kg) (22 m/s)²
KE = (1/2) (2,000 kg) (22 m/s x 22 m/s)
KE = (1/2) (2,000 kg) (484 m²/s²)
I'm <u><em>sure</em></u> you can finish it off from this point, and pick the correct choice.
Answer:
i think the answer is letter c
To solve this problem we will start from the definition of energy of a spring mass system based on the simple harmonic movement. Using the relationship of equality and balance between both systems we will find the relationship of the amplitudes in terms of angular velocities. Using the equivalent expressions of angular velocity we will find the final ratio. This is,
The energy of the system having mass m is,

The energy of the system having mass 2m is,

For the two expressions mentioned above remember that the variables mean
m = mass
Angular velocity
A = Amplitude
The energies of the two system are same then,



Remember that

Replacing this value we have then


But the value of the mass was previously given, then



Therefore the ratio of the oscillation amplitudes it is the same.
Answer:
a)0.48 m/s
b) 0.583 m/s
Explanation:
As the wagon rolls,
momentum'p'= m x v => 95.8 x 0.530 = 50.774 Kgm/s
(a)Rock is thrown forward,
momentum of rock = 0.325 x 15.1 = 4.9075 Kgm/s
Conservation of momentum says momentum of wagon is given by
50.774 - 4.9075 = 45.8665
Therefore, Speed of wagon = 45.8665 / (95.8-0.325) = 0.48 m/s
(b) Rock is thrown backward,
momentum of wagon = 50.774 + 4.9075 = 55.68 Kgm/s
Therefore, speed of wagon = 55.68 / (95.8-0.325) = 0.583 m/s