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pentagon [3]
3 years ago
13

FIRST PERSON MARKED BRAINLIEST! EASY 7TH GRADE SCIENCE QUESTION!!!

Physics
2 answers:
vodka [1.7K]3 years ago
7 0

Answer:

refraction

Explanation:

zavuch27 [327]3 years ago
3 0

Answer:

refraction

Explanation:

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Sedaia [141]

Blu !  The formula is right THERE, IN the question.  All you have to do is plug numbers into it.

The formula:  Kinetic Energy = 1/2 m v²

' m ' is 2,000 kg

' v ' is 22 m/s

Now pluggum in:

KE = (1/2) (2,000 kg) (22 m/s)²

KE = (1/2) (2,000 kg) (22 m/s x 22 m/s)

KE = (1/2) (2,000 kg) (484 m²/s²)

I'm <u><em>sure</em></u> you can finish it off from this point, and pick the correct choice.

6 0
3 years ago
WASSCE
Ratling [72]

Answer:

i think the answer is letter c

5 0
3 years ago
Two vertical springs have identical spring constants, but one has a ball of mass m hanging from it and the other has a ball of m
OverLord2011 [107]

To solve this problem we will start from the definition of energy of a spring mass system based on the simple harmonic movement. Using the relationship of equality and balance between both systems we will find the relationship of the amplitudes in terms of angular velocities. Using the equivalent expressions of angular velocity we will find the final ratio. This is,

The energy of the system having mass m is,

E_m = \frac{1}{2} m\omega_1^2A_1^2

The energy of the system having mass 2m is,

E_{2m} = \frac{1}{2} (2m)\omega_1^2A_1^2

For the two expressions mentioned above remember that the variables mean

m = mass

\omega =Angular velocity

A = Amplitude

The energies of the two system are same then,

E_m = E_{2m}

\frac{1}{2} m\omega_1^2A_1^2=\frac{1}{2} (2m)\omega_1^2A_1^2

\frac{A_1^2}{A_2^2} = \frac{2\omega_2^2}{\omega_1^2}

Remember that

k = m\omega^2 \rightarrow \omega^2 = k/m

Replacing this value we have then

\frac{A_1}{A_2} = \sqrt{\frac{2(k/m_2)}{(k/m_1)^2}}

\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{m_1}{m_1}}

But the value of the mass was previously given, then

\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{m}{2m}}

\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{1}{2}}

\frac{A_1}{A_2} = 1

Therefore the ratio of the oscillation amplitudes it is the same.

5 0
3 years ago
How can two objects with different masses be in balanced equilibrium on a beam with a pivot at the beam center of mass
Elena L [17]

Answer is given below

Explanation:

  • Since the two objects have different masses, their weight varies.  For balance, they must be unequal from the center
  • The lower weight should be placed at a greater distance from the center on one side, and a shorter distance from the center point on the other side, compared to the heavier weight.
  • The sum of the moments of the energies must be zero.
3 0
4 years ago
A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total
Harlamova29_29 [7]

Answer:

a)0.48 m/s

b) 0.583 m/s

Explanation:

As the wagon rolls,

momentum'p'= m x v => 95.8 x 0.530 = 50.774 Kgm/s

(a)Rock is thrown forward,

momentum of rock = 0.325 x 15.1 =  4.9075 Kgm/s

Conservation of momentum says momentum of wagon is given by

50.774 - 4.9075 = 45.8665

Therefore, Speed of wagon = 45.8665 / (95.8-0.325) = 0.48 m/s

(b) Rock is thrown backward,

momentum of wagon = 50.774  + 4.9075 = 55.68  Kgm/s

Therefore, speed of wagon = 55.68 / (95.8-0.325) = 0.583 m/s

4 0
4 years ago
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