Answer:
the expression of current in the loop enclosed to the left of the capacitor plate is
Explanation:
As we know by Ampere's law that line integral of magnetic field around a closed loop is proportional to the current enclosed in the path
So we will have
so we have
so above is the expression of current in the loop enclosed to the left of the capacitor plate
<h2>
Answer:</h2><h2><u>QUESTION①)</u></h2>
✔First you have to calculate the light's speed in the glass,
<em>You know that in the air and in the void (where the refraction index n is zero) the light's speed C corresponds to 3,0 x 10^8 m/s</em>
So We have :
<em>V = C/n </em>
- V = 3,0 x 10^8/1,56
- V ≈ 1,92 x 10^8 m/s
✔ Now, you know the light's speed in glass, and you know that : the wavelength λ is the quotient of light's speed V on its frequency ν, so :
<em>λ = V/ ν </em>
- λ = 1,82 x 10^8/5,70 x 10^14
- λ ≈ 3.40 x 10^-7 m
- λ ≈ 340 nm
Answer:
When the electric force between two charged objects change, the distance between the objects increases in Iicreasing the separation distance between objects and decreases the force of attraction or repulsion between objects.
Hope it helps.
Answer:
(a) Electrostatic force F=4.51×10⁻¹⁷N
(b) Number of electron n=4425 electrons
Explanation:
Given data
Charges q₁=q₂= -7.08×10⁻¹⁶C
Distance r=1.00cm =0.01 m
To find
(a) Electrostatic force F
(b) Number of electron n
Solution
For (a) Electrostatic force
From Coulombs law we know that
For (b) number of electron n
The number of electron on the drop that giving it its imbalance is the total charge divided by charge of electron
As we now that charge of electron e= -1.6×10⁻¹⁹C