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2 years ago

What evidence did astronomers use to prove jets travel in opposite directions?

2 answers:

7 0

The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.

<h3>Who are the astronomers?</h3>

Astronomer is a person who study astronomy which is a scientific study that has to do with space, space bodies, comets, planets, stars and so on.

Therefore, The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.

Learn more about astronomers below.

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klio [65]2 years ago

7 0

Spectral lines from fast-moving red- and blue-shifted ionized gas

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Give a example of scalar quantity

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speed, volume, mass, temperature and power

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3 years ago

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Find the net force for <br> 10 N<br> 10 N<br> 25degree<br> 5N<br> 5N

icang [17]

Answer:

30n

Explanation:

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3 years ago

The speed of light in vinegar is 2.30 x 10^8 m/s. Determine the index of refraction. (2

pantera1 [17]

Answer:

$n _{v} = \frac{c}{v} \\ = \frac{3 \times {10}^{8} }{2.30 \times {10}^{8} } \\ = 1.30$

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3 years ago

What is the fastest the block can be spun at without breaking with the block weighing 10kg and spinning horizontally with a 2m s

larisa86 [58]

The fastest speed before the string breaks is 9.5 m/s

Explanation:

The motion of the block is a uniform circular motion, which is a circular motion with constant speed. The force that keeps the block in circular motion is called centripetal force; its direction is towards the centre of the circle and its magnitude is given by:

$F=m\frac{v^2}{r}$

where

m is the mass of the block

v is its speed

r is the radius of the circle

In this problem, the centripetal force is provided by the tension in the string, T, so we can write:

$T=m\frac{v^2}{r}$

The string breaks when the centripetal force becomes larger than the maximum tension in the string:

$T_{max}$

Re-arranging the equation for v,

$v>\sqrt{\frac{Tr}{m}}$

and here we have:

T = 450 N

m = 10 kg

r = 2 m

Substituting,

$v>\sqrt{\frac{(450)(2)}{10}}=9.5 m/s$

So, the fastest speed before the string breaks is 9.5 m/s.

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7 0

3 years ago

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

Sedaia [141]

Answer:

$a_2\ =\ -33.65\ m/s^2$

Explanation:

Given,

For the first rocket,

Initial velocity of the first rocket A = $u_1\ =\ 4600\ m/s.$

Acceleration of the first rocket = $a_1\ =\ -18\ m/s^2$

For the second rocket,

Initial velocity of the second rocket B = $u_2\ =\ 8200 m/s.$
Displacement of both the rockets A and B = s = 0 m

Fro the first rocket,

Let 't' be the time taken by the first rocket A for whole the displacement

$\therefore s\ =\ u_1t\ +\ \dfrac{1}{2}a_1t^2\\\Rightarrow 0\ =\ 4600t\ -\ 0.5\times 18t^2\\\Rightarrow t\ =\ \dfrac{4600}{0.5\times 18}\\\Rightarrow t\ =\ 511.11 sec$

Let $a_2$ be the acceleration of the second rocket B for the same time interval

from the kinematics,

$\therefore s\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s\ =\ u_2t\ +\ \dfrac{1}{2}a_2t^2\\\Rightarrow a_2\ =\ \dfrac{2s\ -\ 2u_2t}{t^2}\\\Rightarrow a_2\ =\ \dfrac{0\ -\ 2u_2t}{t^2}\\$

$\Rightarrow a_2\ =\ -\dfrac{2u_2}{t}\\\Rightarrow a_2\ =\ -\dfrac{2\times 8600}{511.11}\\\Rightarrow a_2\ =\ -33.65\ m/s^2$

Hence the acceleration of the second rocket B is -33.65\ m/s^2.

6 0

3 years ago