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maw [93]
3 years ago
14

How many oxygen atoms are in 3.45 mol CaCO3

Chemistry
1 answer:
kobusy [5.1K]3 years ago
5 0

Answer:

The formula tells us that each mole of CaCO3 contains 3 moles of Oxygen. Then 3 moles of CaCO3 would contain 3 X 3 or 9 moles of Oxygen. I mole is define as avogadro’s number of units. Avogadro’s number is 6.02 X 10^23. so the answer is 3 X 3 X 6.02 X 10^23. = 5.42 X 10^24

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Can you guys help me answer question 5 on homogeneous mixture tysm
hjlf

Answer:

Hope this helped :) good luck! ❤️

Explanation:

A <em>coolant solution</em> is a <u><em>homogeneous </em></u>mixture because the coolant particles are not chemically combined with the water (keep their properties) and they are evenly distributed throughout the water.

7 0
3 years ago
Review this balanced neutralization reaction: HBr + KOH KBr + H2O. Which substance is the base?
Olegator [25]
B KOH
I would say this is the base for the compound substance
8 0
4 years ago
HELP ME PLEASE
lions [1.4K]

Answer:

A

Explanation:

Definitely not in the cell theory

3 0
3 years ago
How long does it take for a 12.62g sample of ammonia to heat from 209K to 367K if heated at a constant rate of 6.0kj/min? The me
Georgia [21]
First, consider the steps to heat the sample from 209 K to 367K.

1) Heating in liquid state from 209 K to 239.82 K

2) Vaporaizing at 239.82 K

3) Heating in gaseous state from 239.82 K to 367 K.


Second, calculate the amount of heat required for each step.

1) Liquid heating

Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol

=> number of moles = 12.62 g / 17 g/mol = 0.742 mol

Heat1 = #moles * heat capacity * ΔT

Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J

2) Vaporization

Heat2 = # moles * H vap

Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J

3) Vapor heating

Heat3 = #moles * heat capacity * ΔT

Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J

Third, add up the heats for every steps:

Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J

Fourth, divide the total heat by the heat rate:

Time = 22,466.3 J / (6000.0 J/min) = 3.7 min

Answer: 3.7 min


3 0
3 years ago
A sample of gas has a volume of 2.36 L at a temperature of 53.00 °C. The gas sample is heated to a temperature of 139.00 °C (ass
Liono4ka [1.6K]

Answer:

The volume increases because the temperature increases and is 2.98L

Explanation:

Charles's law states that the volume of a gas is directely proportional to its temperature. That means if a gas is heated, its volume will increase and vice versa. The equation is:

V₁/T₁ = V₂/T₂

<em>Where V is volume and T is absolute temperature of 1, initial state, and 2, final state of the gas.</em>

In the problem, the gas is heated, from 53.00°C (53.00 + 273.15 = 326.15K) to 139.00°C (139.00 + 273.15 = 412.15K).

Replacing in the Charles's law equation:

2.36L / 326.15K= V₂/412.15K

<h3>2.98L = V₂</h3>

<em />

5 0
4 years ago
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