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yanalaym [24]
3 years ago
12

I need Help please Correct Answer mark you as the Brainleist.

Mathematics
2 answers:
telo118 [61]3 years ago
7 0

Answer:

volume=4/3πr³

=4/3×22/7×2.7³

=82.4

82cm³

julia-pushkina [17]3 years ago
7 0
<h2>Answer:</h2><h2>82</h2>

Hope this will help you.

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Jeremy bought a 5-kilogram can of peanuts for $4.50. What is the unit price?
Goryan [66]

Answer:

$0.90

Step-by-step explanation:

you would divide it by 5

$4.50/5=$0.90

hope this helps

brainliest?

6 0
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Help! QUICK! NO BOTS!
White raven [17]

Answer:

number 2 or 4 but i think 2

Step-by-step explanation:

6 0
3 years ago
Sequences:
IrinaK [193]

Answer:

A.

  • aₙ = (2n + 3)/4

<u>The first 5 terms:</u>

  • a₁ = (2*1 + 3) / 4 = 5/4
  • a₂ = (2*2 + 3) / 4 = 7/4
  • a₃ = (2*3 + 3)/ 4 = 9/4
  • a₄ = (2*4 + 3) / 4 = 11/4
  • a₅ = (2*5 + 3) / 4 = 13/4

B.

  • aₙ = (n - 3)/(n - 2)

<u>The first 5 terms:</u>

  • a₁ = (1 - 3) / (1 - 2) = 2
  • a₂ = (2 - 3) / (2 - 2) = undefined
  • a₃ = (3 - 3)/ (3 - 2) = 0
  • a₄ = (4 - 3) / (4 - 2) = 1 / 2
  • a₅ = (5 - 3) / (5 - 2) = 2 / 3
7 0
3 years ago
The blades of a windmill turn on an axis that is 40 feet from the ground. The blades are 15 feet long and complete 3 rotations e
astraxan [27]

Answer:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

Step-by-step explanation:

In this problem the amplitude of the sinusoidal function is given by the length of the blades.

a = 15\ ft

The mill is 40 feet above the ground, therefore the function must be displaced 40 units up on the y axis. So:

k = 40\ ft

We know that the blades have an angular velocity w = 3 rotations per minute.

One rotation = 2\pi

1 minute = 60 sec.

So:

w = \frac{3(2\pi)}{60}\ rad/s

w = \frac{\pi}{10}\ rad/s

Finally:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

3 0
4 years ago
Read 2 more answers
How to prove that IC is parallel with AB?
Karo-lina-s [1.5K]
There is something wrong with drawing. IC intercepts with AB at A.
7 0
3 years ago
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