Answer: 4575N
Explanation:
For y component, W = mgcosø
W = 500×9.8cos21
W = 4574.54N
Find the diagram in the attached file
Answer:
e.)At twice the distance, the strength of the field is E/4.
Explanation:
The strength of the electric field at a certain distance from a point charge is given by:

where
k is the Coulomb's constant
Q is the charge
r is the distance from the point charge
In this problem, the distance from the point charge is doubled:
r' = 2r
So the new electric field strength is

so, at twice the distance the strength of the field is E/4.
In several of the questions you've posted during the past day, we've already said that a wave with larger amplitude carries more energy. That idea is easy to apply to this question.
I believe it is acceleration!