Answer:
I could create a slower reaction because the particles might be moving slower due to the cold. if it was warm there will be a faster reaction. similar to the elements movements in solids and liquids.
Answer:
A disease caused by a plasmodium parasite, transmitted by the bite of infected mosquitoes.
The severity of malaria varies based on the species of plasmodium.
Symptoms are chills, fever, and sweating, usually occurring a few weeks after being bitten.
People traveling to areas where malaria is common typically take protective drugs before, during, and after their trip. Treatment includes antimalarial drugs.
Explanation:
Answer:
2666.7 hours
Explanation:
The key to solve this problem is that we are given the propane gas consumed in one hour by giving us the information of the volume consumed at 1 atm, 298 K (25 +273). Using the gas law we can calculate the rate of consumption of propane per hour, and from here we can calculate its mass and converting it to gallons and finally diving the 400 gallos by this number.
PV = nRT ∴ n = PV/RT
n = 1 atm x 165 L/ (0.08206 Latm/kmol x 298 K ) = 6.75 mol propane
Mass propane :
6.75 mol x 44 g/mol = 296.88 g
convert this to Kg:
296.88 g/ 1000 g/Kg = 0.30 Kg
calculate the volume in liters this represents by dividing by the density:
0.30 Kg / 0.5077 Kg/L = 0.59 L
changing this to gallons
0.59 L x 1 gallon/3.785 L = 0.15 gallon
and finally calculate how many hours the 400 gallons propane tank will deliver
400 gallon/ 0.15 gallon/hr = 2666.7 hr
Complete Question
Magnesium sulfate forms a hydrate with the formula 
. What is the maximum amount of water (in grams) that can be removed from 15 ml of toluene by the addition of 200 mg of anhydrous magnesium sulfate? The molar mass of 
is 120.4 g/mol; H20 = 18 g/mol.
Answer:
The value is 
of 
Explanation:
From the question we are told that
The volume of toluene is 
The mass of anhydrous magnesium sulfate is 
The formula of the hydrate is
The molar mass of is 
From the formula given we see that
1 mole of 
wil remove 7 moles of to for the given formula
Hence
120.4 g (1 mole) will remove 7 moles (7 * 18 g = 126 g ) of to for the given formula
Therefore 1 g of x g of
So
![x = \frac{x]126 * 1}{ 120.4 }](https://tex.z-dn.net/?f=x%20%20%3D%20%20%5Cfrac%7Bx%5D126%20%2A%20%201%7D%7B%20120.4%20%7D)
=> 
From our calculation we obtained that
1 g of will remove of
Then
of will remove z g of of
So
=>
=> of
