Answer: 44.8 L
Explanation:
To find the volume, we would need to use the ideal gas law.
Ideal Gas Law: PV=nRT
We take the given information and plug it into the equation, but first, we have to manipulate the equation so that we are finding volume.
P= 1.00 atm (STP)
T= 273.15 K (STP)
R= 0.08206 Latm/Kmol
n=
Answer:
We need 92.3 grams of sodium azide
Explanation:
Step 1: Data given
Mass of nitrogen gas = 59.6 grams
Molar mass of nitrogen gas = 28.0 g/mol
Molar mass of sodium azide = 65.0 g/mol
Step 2: The balanced equation
2NaN3 → 2Na + 3N2
Step 3: Calculate moles nitrogen gas
Moles N2 = mass N2 / molar mass N2
Moles N2 = 59.6 grams/ 28.0 g/mol
Moles N2 = 2.13 moles
Step 4: Calculate moles NaN3
for 2 moles NaN3 we'll have 2 moles Na and 3 moles N2
For 2.13 moles N2 we need 2/3* 2.13 = 1.42 moles NaN3
Step 5: Calculate mass NaN3
Mass NaN3 = Moles NaN3 * molar mass NaN3
Mass NaN3 = 1.42 moles * 65.0 g/mol
Mass NaN3 = 92.3 grams
We need 92.3 grams of sodium azide
The answer is B
Hello, I have written out the unbalanced equation for this problem here:
SO3 (g) + H2O (l) ->H2SO4(aq)
Typical oxidation states of copper are
C u + l, and C U +I l cuprous and cupric ions.