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Novay_Z [31]
3 years ago
13

An electron is in a region outside the nucleus

Chemistry
1 answer:
harkovskaia [24]3 years ago
3 0
Is that a question? Doesnt seem like it
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Which of the following always changes when a substance undergoes a chemical change?
Ronch [10]

Answer:

C

Explanation:

All chemical reactions will show a change in color.

8 0
3 years ago
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To determine the mass of CO2 that forms from a given mass of CaCO3, which of the following must be known? Check all that apply.
ZanzabumX [31]

To determine the mass of CO₂, the following must be known :

  • the molar mass of CaCO₃
  • the mole ratio of CaCO₃ to CO₂
  • the molar mass of CO₂
<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

Given the mass of  CaCO₃, so to determine the mass of CO₂ :

1. Find the mol of  CaCO₃ from the molar mass of  CaCO₃

\tt n_{CaCO_3}=\dfrac{mass~CaCO_3}{MW~CaCO_3}

2. Find the mole ratio of  CaCO₃ : CO₂(from equation = 1 : 1)

\tt n_{CaCO_3}\div n_{CO_2}=1\div 1

3. Find the mass of CO₂ from the molar mass of CO₂

\tt mass_{CO_2}=n_{CO_2}\times MW_{CO_2}

3 0
3 years ago
Read 2 more answers
What does it mean to dilute a solution?
LenKa [72]

Answer:

Dilution is the process of decreasing the concentration of a solute in a solution, usually simply by mixing with more solvent like adding more water to the solution

7 0
3 years ago
How many grams of H2 can be formed from 54.6 grams of NH3 in the following reaction? 2NH3 (g) --&gt; 3H2 (g) + N2 (g)
Strike441 [17]

Answer:

9.64g

Explanation:

The balanced equation for the reaction is given below:

2NH3 (g) —> 3H2 (g) + N2 (g)

Next, we need to calculate the mass NH3 that decomposed and the mass of H2 produced from the balanced equation. This is illustrated below:

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 that decomposed from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 produced from the balanced equation = 3 x 2 = 6g.

Now, we can obtain the mass of H2 formed from 54.6g of NH3 as follow:

From the balanced equation above,

34g of NH3 decomposed to produce 6g of H2.

Therefore, 54.6g of NH3 will decompose to produce = (54.6x6)/34 = 9.64g of H2

Therefore, 9.64g of H2 can be obtained from 54.6g of NH3.

3 0
3 years ago
Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C.
evablogger [386]

Answer:

The total amount of heat needed = 72.2116  kJ

Explanation:

Given that ;

the mass of acetic acid = 120.0 g

The initial temperature T_1 = 16.7 °C  = (16.7 + 273.15 ) K = 298.85 K

The standard molar mass of acetic acid = 60.052  g/mol

Thus ; we can determine the number of moles of acetic acid;

number of moles of acetic acid = mass of acetic acid/ molar mass of acetic acid

number of moles of acetic acid = 120.0 g/ 60.052 g/mol

number of moles of acetic acid =  1.998 moles

For acetic acid:

The standard boiling point  T_2 = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K

The enthalpy of vaporization of acetic acid \Delta H_{vap} = 23.7 kJ/mol

The heat capacity of acetic acid   c = 2.043  J/g.K

The change in temperature Δ T = T_2 - T_1

Δ T = (391.25 - 289.85)K

Δ T = 101.4 K

The amount of heat needed to bring the liquid acetic acid at 16.7°C to its boiling point is ;

q = mcΔT

From our values above;

q = 120 g ×  2.043  J/g.K × 101.4 K

q = 24859.2  J

q = 24859 /1000 kJ

q = 24.859 kJ

we have earlier calculated our number of moles o f acetic acid to be 1.998 moles;

Thus;

The needed amount of heat = \Delta_{vap} *numbers \ of  \ moles

The needed amount of heat = 23.7 \ kJ/mol * 1.998 \ moles

The needed amount of heat = 47.3526 kJ

Hence;

The total amount of heat needed = 24.859 kJ + 47.3526 kJ

The total amount of heat needed = 72.2116  kJ

4 0
3 years ago
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