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Novay_Z [31]
3 years ago
13

An electron is in a region outside the nucleus

Chemistry
1 answer:
harkovskaia [24]3 years ago
3 0
Is that a question? Doesnt seem like it
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When sodium metal is added to water, an orange flame is observed on the metal surface. Based on this observation, what can best
pickupchik [31]
All you can conclude is that something must be burning with an orange flame.

Actually, the "something" that must be burning is the hydrogen that is produced when the sodium reacts with the water:

2Na + 2H₂O → 2NaOH + H₂ + heat

So much heat is produced that the hydrogen catches fire and some of the sodium evaporates into the flame.

The electrons in the sodium atoms get "excited" in the flame. When they drop back to a lower energy level, they emit energy in the form of an orange-yellow light.
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4 years ago
A team of engineers has decided to design a new shoe for people suffering
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The answers to this question is b, I did this on Plato
4 0
3 years ago
72. how is it possible to recognize the end point of a titration?
Alla [95]
When the solution used begins to change color and stays the new color for at least 30 seconds we are able to tell that the solution has reached the end point of titration
3 0
2 years ago
A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 10
masya89 [10]

<u>Answer:</u> The molar mass of unknown gas is 367.12 g/mol

<u>Explanation:</u>

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

\text{Rate}=\frac{V}{t}

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

So,

\left(\frac{\frac{V_{X}}{t_{X}}}{\frac{V_{O_2}}{t_{O_2}}}\right)=\sqrt{\frac{M_{O_2}}{M_{X}}}

We are given:

Volume of unknown gas (X) = 1.0 L

Volume of oxygen gas = 1.0 L

Time taken by unknown gas (X) = 105 seconds

Time taken by oxygen gas = 31 seconds

Molar mass of oxygen gas = 32 g/mol

Molar mass of unknown gas (X) = ? g/mol

Putting values in above equation, we get:

\left(\frac{\frac{1.0}{105}}{\frac{1.0}{31}}\right)=\sqrt{\frac{32}{M_X}}\\\\M_X=367.12g/mol

Hence, the molar mass of unknown gas is 367.12 g/mol

3 0
4 years ago
Classify each salt as acidic, basic, or neutral? -nh4cl -ca(no32
vichka [17]
The pH of salt depends on the component acid and base that comprise them. For example, if the salt is made up of strong acid and weak base then, the salt is acidic. If the salt is formed from strong base and weak acid then, the salt is basic. For this item, NH4Cl is acidic and also Ca(NO3)2 is acidic. 
3 0
3 years ago
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