Question

A jet liner must reach a speed of 82 m/s for takeoff. If the

Answer 1

Answer:

The acceleration that the jet liner that must have is 2.241 meters per square second.

Explanation:

Let suppose that the jet liner accelerates uniformly. From statement we know the initial ($v_{o}$) and final speeds ($v_{f}$), measured in meters per second, of the aircraft and likewise the runway length ($d$), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed ($a$), measured in meters per square second:

$a = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot d}$

If we know that $v_{o} = 0\,\frac{m}{s}$, $v_{f} = 82\,\frac{m}{s}$ and $d = 1500\,m$, then the acceleration that the jet must have is:

$a = \frac{\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (1500\,m)}$

$a = 2.241\,\frac{m}{s^{2}}$

The acceleration that the jet liner that must have is 2.241 meters per square second.