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3 years ago

(-2,4) (8,10) slope intercept form

Mathematics

1 answer:

kherson [118]3 years ago

3 0

Answer:

Step-by-step explanation:

1) Use the given coordinate points to find the slope

m= $\frac{10-4}{8-(-2)}$ m= $\frac{3}{5}$

2) plug the slope into slope-intercept form

y= $\frac{3}{5}$ x+b

3) choose one point to use to plug into the equation to solve for b

4= $\frac{3}{5}$ (-2)+b

4) solve for b.

b= $\frac{26}{3}$

5) substitute the value for b into equation from step 2

y= $\frac{3}{5}$ x+ $\frac{26}{3}$

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3 years ago

which of the following would be a line of reflection that would map ABCD onto itself? A(-3,0) B(-3,2) C(-1,2) D(-1,0)

Aleksandr-060686 [28]

The line of reflection that would map ABCD onto itself is the line y = x + 3

<h3>What is a transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>translation, rotation, reflection and dilation.</em>

Dilation is the increase or decrease in the size of a figure.

The equation of the line passing through A(-3, 0) and C(-1, 2) is:

y-0 = [(2-0)/(-1-(-3))](x - (-3)]

y = x + 3

The line of reflection that would map ABCD onto itself is the line passing through AC which is y = x + 3

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2 years ago

zodwa needs R450550.00 to buy a house, the bank approved her loan for the full amount at an interest rate of 25% per year, compo

adell [148]

Answer:

I'll setup the problem and leave the computation to you

Step-by-step explanation:

The equation to calculate fixed payments

$P = \frac{r(PV)}{1- {(1 + r)}^{ - n} }$

P= payments

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if you have questions, put them in the comment

6 0

3 years ago

A statistics teacher started class one day by drawing the names of 10 students out of a hat and asked them to do as many pushups

HACTEHA [7]

Answer: b. 8.56 to 21.44

Step-by-step explanation:

Let $\mu$ be the mean number of pushups that can be done.

As per given , we have

Sample size : n= 10

Degree of freedom = n-1=9

Sample mean : $\overline{x}=15$

Sample standard deviation : $s=9$

Significance level : α=1-0.95=0.05

From t- distribution table ,

Critical two -tailed t-value for α=0.05 and df = 9 is

$t_{\alpha/2, 9}=t_{0.025,9}=2.2622$

Confidence interval for $\mu$ is given by :-

$\overline{x}\pm t*\dfrac{s}{\sqrt{n}}$

$=15\pm (2.2622)\dfrac{9}{\sqrt{10}}\\\\\approx 15\pm 6.44=(15-6.44,\ 15+6.44)\\\\=(8.56,\ 21.44)$

Hence, the 95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.

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3 years ago

The strip below is divided into 10 equal parts. Fill in the missing fractions and percentages.Note that your fractions don't nee

boyakko [2]

Answer:

1. First box, the missing fraction = 1/10

2. For the 2nd box

a. The missing fraction = 3/10

b. Percentage = 30%

3. For 7/10

Percentage = 70%

Step-by-step explanation:

From the question given above, the following data were obtained:

The strip is divided into 10 equal parts.

1. For the first box:

The missing fraction = 1/10

2. For the 2nd box

a. The missing fraction = 3/10

b. Percentage = 3/10 × 100 = 30%

3. For 7/10

Percentage = 7/10 × 100 = 70%

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3 years ago