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asambeis [7]
3 years ago
13

If a ball is rolling 5 pounds of force how much force will be needed to stop the ball from rolling and why?

Physics
1 answer:
Alisiya [41]3 years ago
7 0

Answer:

5 pounds of force in the opposite direction

Explanation:

If a ball is rolling 5 pounds of force, to stop this ball, we would require 5 pounds of force in the opposite direction.

A force is a pull or push on a body. It can be with contact or without any contact.

Therefore, to stop this body direct an equal and opposite amount of force to it.

Based on Newton's third law of motion "action and reaction forces are equal and opposite in their actions"

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What would be the resulting charge of carbon (C) after this element loses four electrons?
Sladkaya [172]

Answer:

Carbon will become positively charged.

The charge of Carbon will be +4.

Explanation:

The charge of Carbon will be +4.

In the periodic table, elements that give out  or lose electrons during electrochemical combinations are called electropositive elements. If carbon loses electrons during the chemical combination, Carbon will become positively charged, with a valency equal to the number of electrons that it lost.

This will make carbon have a charge of +4

7 0
3 years ago
II) A 0.40-kg ball, attached to the end of a horizontal ord, is rotated in a circle of radius 1.3 m on a friction- less horizont
Lostsunrise [7]

Hi there!

In this instance, the object spinning in a horizontal circle will experience a net force in the horizontal direction due to tension.

The net force is equivalent to the centripetal force, so:

∑F = T

mv²/r = T

Solve for v:

v = √rT/m

v = 13.96 m/s

3 0
3 years ago
What is a charge-coupled device (CCD), and how is it used in astronomy?
Sedaia [141]

Answer:

Charge-coupled device  (CCD) is a device that receives and transfers an electrical charge to the next region

Explanation:

Charge-coupled device  (CCD) is a device that receives and transfers an electrical charge to the next region where it can be modified like changing it to a electronic value.

In astronomy, high-powered telescopes can be used with CCD device image sensor cameras. The imaging system can concentrate for a number of hours on one place in space once the Earth's rotation synchronizes with the telescope.

6 0
4 years ago
HELP!!!
FinnZ [79.3K]
A and B i think is the answer
7 0
3 years ago
Read 2 more answers
A catapult with a radial arm 3.81 m long accelerates a ball of mass 18.2 kg through a quarter circle. The ball leaves the appara
saw5 [17]

Answer:

(a)\alpha = 53.73 m/s^2

(b)   I =428 kgm^2

(c)\tau = 428 \times 53.73  = 22996 .44Nm

Explanation:

GIVEN

mass = 18.2 kg

radial arm length = 3.81 m

velocity = 49.8 m/s

mass of arm = 22.6 kg

we know using relation between linear velocity and angular velocity

\omega = \frac{v}{l}

\omega = \frac{49.8}{3.81} \\\omega = 12.99 rad/s

for  angular acceleration, use the following equation.

\omega _{f}^2 = \omega_{i}^2+2\alpha\theta

since \omega _{i} = 0

here  for one circle is 2 π radians.   therefore for one quarter of a circle is π/2 radians

so   for one quarter \theta = \frac{\pi }{2}

(12.99)^2 = 2\alpha(\frac{\pi }{2})

on solving

\alpha = \frac{168.74}{\pi }\\\alpha = 53.73 m/s^2

(b)

For the catapult,

moment of inertia

I = \frac{1}{2}MR^2

I = \frac{1}{2} \times 22.6\times 3.81 \times 3.81\I = 164kg m^2

For the ball,

I = MR^2

I = 18.2 \times 14.51

I = 264 kgm^2

so total moment of inertia =  428 kgm^2

(c)

\tau = I\alpha

\tau = 428 \times 53.73  = 22996 .44Nm

3 0
3 years ago
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