Answer:
New volume V2 = 92.7 Liter (Approx)
Explanation:
Given:
V1 = 106 l
T1 = 45 + 273.15 = 318.15 K
P1 = 740 mm
T2 = 20 + 273.15 = 293.15 K
P2 = 780 mm
Find:
New volume V2
Computation:
P1V1 / T1 = P2V2 / T2
(740)(106) / (318.15) = (780)(V2) / (293.15)
New volume V2 = 92.7 Liter (Approx)
Answer:
I think that you want no, of moles
Explanation:
no, of mole of this amount= 15/44 = 0.341 mole
The electron subshells in the atoms of group 5a elements discourage electron addition.
This is because the subshells in the group 5a elements are already half-filled, which is a more stable electronic configuration that that which would be achieved if another electron was added.
Meanwhile, group 4a elements' subshell becomes half-filled when an electron is added, making them somewhat stable. This means that they prefer electron addition.
Answer:
The final concentration is 0.288 M (approximately)
Explanation:
Using dilution formula:
C1V1 = C2V2
Where C1 is the initial concentration
C2 is the final concentration
V1 is the initial volume
V2 is the final volume
In the first dilution, C1 = 1.8M,
V1 =71mL, V2 = 218mL from the formula C2 = 1.8 ×71/281
=0.5862M
In the second dilution,
C1 = 0.5862M, V1 = 109mL, V2 = 222 mL (109+113)
C2 = 0.5862 × 109 ÷ 222
= 0.288 M (approximately) assuming volume is additive.