Answer:
375 K
Explanation:
Using the experssion shown below as:

At vaporization point, the liquid and the gaseous phase is in the equilibrium.
Thus,

So,

Given that:

Also, 1 kJ = 10³ J
So,


So, temperature is :


<u>T= 375 K</u>
From the equation:
4mol Li react with 1 mol O2
Molar mass Li = 7g/mol
mol in 84g Li = 84/7 = 12 mol Li
From the equation - 12 mol Li will react with 3 mol O2
At STP 1 mol O2 has volume = 22.4L
<span>
At STP 3 mol O2 has volume = 3*22.4 = 67.2L O2 gas will react. </span>
The specific heat of aluminum is 0.902 J/gC. E=m*cp*delta T, or
125*0.902*(95.5-19)= 8630 J
The molecules in gas are farther apart and have more room to bounce around than liquid