Question

On a hot day, a 15.0 kg window increased from 20.0 degrees C to 26.7 degrees C. How much heat energy did the glass window absorb? (specific heat of glass = 0.840 J/gC)

Answer 1

Answer: The heat energy absorbed by the glass window is 84420 J.

Explanation:

Given: Mass = 15.0 kg (1 kg = 1000 g) = 15000 g

Specific heat capacity = $0.840^{o}C$

Initial temperature = $20^{o}C$

Final temperature = $26.7^{o}C$

Formula used to calculate heat energy is as follows.

$q = m \times C \times (T_{2} - T_{1})$

where,

q = heat energy

m =  mass of substance

C = specific heat capacity

$T_{1}$ = initial temperature

$T_{2}$ = final temperature

Substitute the values into above formula as follows.

$q = m \times C \times (T_{2} - T_{1})\\= 15000 g \times 0.840J/g^{o}C \times (26.7 - 20.0)^{o}C\\= 84420 J$

Thus, we can conclude that heat energy absorbed by the glass window is 84420J.