We know, F = m*a
Here, F = 600-400 = 200 N downwards
m = 60 Kg
Substitute their values,
a = 200/60
a = 20/6
a = 10/3
a = 3.33 m/s² downwards
In short, Your Answer would be 3.33 m/s² downwards
Hope this helps!
Using the Debroglies equation,energy can be found,as 1.9773*10*-9
then, energy* wave length= hc
c is the speed of light and is the planks constant.
wave length =1.006*10*-16 m
(186,000 mi/sec) x (3,600 sec/hr) x (24 hr/da) x (365 da/yr)
= (186,000 x 3,600 x 24 x 365) mi/yr
= 5,865,696,000,000 miles per year (rounded to the nearest million miles)
Answer:
Explanation:
This is a simple gravitational force problem using the equation:
where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.
Filling in:
I'm going to do the math on the top and then on the bottom and divide at the end.
and now when I divide I will express my answer to the correct number of sig dig's:
6.45 × 10¹⁶ N
Because gravity is constant
<span>the only force acting in free-fall is gravity which points downward at 9.8 m/s</span>
