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3 years ago

What invisible force will cause you to fall to the earth if you fall off your bed?

Physics

1 answer:

Katyanochek1 [597]3 years ago

8 0

Answer:

The answer to this is falling all the way through the Earth is impossible, since its core is molten. ... As you approached the center of the earth the pull of gravity would decline and eventually (at the center) cease, but inertia would keep you going.

Explanation:

your welcome

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Please help with 4 and 5, thank you :)

allochka39001 [22]

Answer: #4

Sally is faster.

Explanation:

If you multiply Sallies it is going to be less than Jessica's.

6 0

2 years ago

What day of the year is solar time the same as sidereal time?

Illusion [34]

Answer:

I think the answers March 21

6 0

2 years ago

Read 2 more answers

Explain how the basic units are combined to give the derived units of force, velocity and pressure and work

Lorico [155]

#Force

$\\ \sf\longmapsto Force=Mass\times Acceleration$

$\\ \sf\longmapsto Force=kg m/s^2$

$\\ \sf\longmapsto Force=Newton (N)$

#Velocity

$\\ \sf\longmapsto Velocity=\dfrac{Displacement}{time}$

$\\ \sf\longmapsto Velocity=m/s$

#Work

$\\ \sf\longmapsto Work=Force\times Displacement$

$\\ \sf\longmapsto Work=Nm$

$\\ \sf\longmapsto Work=Joules(J)$

5 0

2 years ago

As a transverse wave travels through a rope from left to right, the parts of the rope _______.

kupik [55]

<h3><u>Answer;</u></h3>

Are moving up and down.

As a transverse wave travels through a rope from left to right, the parts of the rope <u>are moving up and down</u>.

<h3><u>Explanation;</u></h3>

Transverse waves occur when a disturbance causes oscillations perpendicular to the propagation, that is the direction of energy transfer.
<em><u>Particles of the medium move perpendicular to the direction the transverse wave itself is moving. For example, if the wave is moving to the right, the particles of the medium are moving up and down.</u></em>
<em><u>Therefore, as a transverse wave travels through a rope from left to right, the parts of the rope are moving up and down.</u></em>

8 0

3 years ago

The electric field everywhere on the surface of a thin, spherical shell of radius 0.770 m is of magnitude 860 N/C and points rad

11111nata11111 [884]

Answer:

(a) $Q = 7.28\times 10^{14}$

(b) The charge inside the shell is placed at the center of the sphere and negatively charged.

Explanation:

Gauss’ Law can be used to determine the system.

$\int{\vec{E}} \, d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E4\pi r^2 = \frac{Q_{enc}}{\epsilon_0}\\(860)4\pi(0.77)^2 = \frac{Q_{enc}}{8.8\times 10^{-12}}\\Q_enc = 7.28\times 10^{14}$

This is the net charge inside the sphere which causes the Electric field at the surface of the shell. Since the E-field is constant over the shell, then this charge is at the center and negatively charged because the E-field is radially inward.

The negative charge at the center attracts the same amount of positive charge at the surface of the shell.

5 0

3 years ago