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Naddika [18.5K]

3 years ago

13

A boy does 465 J of work pulling an empty wagon along level ground with a force of 111 N [31o below the horizontal]. A frictiona

l force of 155 N opposes the motion and is actually slowing the wagon down from an initial high velocity. The distance the wagon travels is

1 answer:

vovikov84 [41]3 years ago

6 0

Can you list the answer's

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A 0.144 kg baseball is moving towards home plate with a speed of 43.0 m/s when it is bunted. the bat exerts an average force of

Ganezh [65]

As per impulse momentum theorem we know that

$F\Delta t = m(v_f - v_i)$

now here we will have

$F = 6.50 \times 10^3 N$

t = 1.30 ms

m = 0.144 kg

$v_i = -43 m/s$

now we need to find final speed using above formula

$(6.50 \times 10^3)(1.30 \times 10^{-3}) = 0.144 ( v_f - (-43))$

$v_f = 15.7 m/s$

so final speed is given as above

6 0

3 years ago

Place /our live /music / important / has / in / an

oksian1 [2.3K]

Answer:

Music has an important place in our lives.

3 0

3 years ago

A cassette recorder uses a plug-in transformer to convert 120 V to 12.0 V, with a maximum current output of 200 mA. What is the

goldfiish [28.3K]

Answer:

20 mA

Explanation:

We have given that the transformer convert 120 V to 12 V means it is a step down transformer

The turn ratio of the transformer is given as $a=\frac{N_1}{N_2}=\frac{V_1}{V_2}=\frac{120}{12}=10$ here $V_!$ is primary voltage and $V_2$ is secondary voltage

As the voltage decreases from primary to secondary so current will increase from primary to secondary

We have given output current that is secondary current so primary that is input current will be less

So input current $=\frac{200}{10}=20mA$

4 0

3 years ago

In a doorknob, the knob is connected to a shaft. When the knob turns, the shaft turns,which moves the door latch. The radius of

HACTEHA [7]

Answer:

`7

Explanation:

i know

4 0

3 years ago

While bats emit a wide variety of sounds, one type emits pulses of sound at a frequency between 39 kHz and 78 kHz. What is the r

sdas [7]

Answer:

The range of wavelengths of the sound is 7692.30 m and 3846.15 m

Explanation:

A bat emits pulses of sound at a frequency between 39 kHz and 78 kHz. It is required to find the range of wavelengths of this sound.

Bat uses ultrasonic waves. It moves with the speed of light.

If f = 39 kHz,

$\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{39\times 10^3}\\\\\lambda=7692.30\ m$

If f = 78 kHz,

$\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{78\times 10^3}\\\\\lambda=3846.15\ m$

So, the range of wavelengths of the sound is 7692.30 m and 3846.15 m.

6 0

3 years ago