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Naddika [18.5K]

3 years ago

13

A boy does 465 J of work pulling an empty wagon along level ground with a force of 111 N [31o below the horizontal]. A frictiona

l force of 155 N opposes the motion and is actually slowing the wagon down from an initial high velocity. The distance the wagon travels is

1 answer:

vovikov84 [41]3 years ago

6 0

Can you list the answer's

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A ballistic pendulum is a device for measuring bullet speeds. One of the simplest versions consists of a block of wood hanging f

jeka94

Answer:

0.043 m upwards

Explanation:

The mass of the bullet, $m_1$ = 0.013 kg

Mass of the ballistic pendulum, $m_2$ = 3 kg

Velocity of the bullet, $v_1$ = 320 m/s

Therefore, from the law of conservation of momentum, we get

$m_1v_1+m_2v_2=m_1v_1^1+m_2v_2^1$

$(0.013 \times 320)+(3 \times 0) = \left(0.013 \times \frac{320}{0}\right) + (3 \times v_2^1)$

$3 \times v_2^1=2.774$

$v_2^1=0.92 \ m/s$

Therefore the required height to rise the block is given by :

$(v_2^1)^2-v_2^2=2gh$

$h=\frac{(v_2^1)^2-v_2^2}{2g}$

$h=\frac{(0.92)^2-0}{2(-9.81)}$

$h=-0.043 \ m$

Therefore, the block moves upwards for 0.043 meters.

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3 years ago

Which statement offers the best reason why it is harder for females to lose body fat and gain muscle than it is for males? A. Fe

Liono4ka [1.6K]

A. Females have lower levels of testosterone than males.

It's the only logical answer, all the other ones can happen to both male and female equally

6 0

4 years ago

Read 2 more answers

Someone plz help me with this problem!!

bagirrra123 [75]

Answer:

C. Selenium

Explanation:

3 0

3 years ago

If a person attempts to read their e-mail while they are riding the bus, they are _______.

Alinara [238K]

Answer:

A

Explanation:

7 0

3 years ago

In the two-slit experiment, monochromatic light of wavelength 600 nm passes through a 19) pair of slits separated by 2.20 x 10-5

kumpel [21]

Explanation:

It is given that,

Wavelength of monochromatic light, $\lambda=600\ nm=6\times 10^{-7}\ m$

Slits separation, $d=2.2\times 10^{-5}\ m$

(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

$d\ sin\theta=n\lambda$ , n = 1

$\theta=sin^{-1}(\dfrac{\lambda}{d})$

$\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})$

$\theta=1.56^{\circ}$

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, $d\ sin\theta=(n+\dfrac{1}{2})\lambda$

$sin\theta=\dfrac{3\lambda}{2d}$

$\theta=sin^{-1}(\dfrac{3\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{3\times 6\times 10^{-7}}{2\times 2.2\times 10^{-5}})$

$\theta=2.34^{\circ}$

Hence, this is the required solution.

4 0

4 years ago