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Gala2k [10]
3 years ago
12

Considering the passage about crude oil, why is distillation the main process for separating the contents of crude oil? Crude oi

l is a homogeneous mixture. Crude oil is a heterogeneous mixture A major byproduct of crude oil is gasoline.
Chemistry
2 answers:
harina [27]3 years ago
5 0

Answer:

Crude oil is a homogeneous mixture.

Explanation:

I got it right.

makvit [3.9K]3 years ago
4 0

Answer: Crude oil is a homogeneous mixture.

Explanation: im doin edge

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Iron(III) oxide and hydrogen react to form iron and water, like this:
Andru [333]

Answer:mmmm popeyes chicken

Explanation:

6 0
2 years ago
The density of an element is 19.3 g/cm^3. What is its density in kg/m^3?
Karolina [17]
First, you need to know 1 kg = 10^3 g. And 1 m^3 = 10^6 m^3. So the 1 g/cm3 = 10^3 kg/m3. So the answer is 1.93*10^4 kg/m3.
5 0
3 years ago
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Assoli18 [71]

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8 0
2 years ago
A given sample of a gas has a volume of 3 liters at a
ycow [4]

Answer:

B) 12

Explanation:

Given parameters:

Initial volume  = 3L

Initial pressure  = 4atm

Final pressure  = 6atm

Unknown:

Final volume  = ?

Solution:

To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

   P₁V₁  = P₂V₂

 P and V are pressure and temperature values

 1 and 2 are initial and final states.

    PV product  = 3 x 4 = 12

7 0
3 years ago
If the half-life of C-14 is 5730 years, how much C-14 would be left from a 5000 year-old sample that started as 150 grams?
serious [3.7K]
<h3>Answer:</h3>

81.9 grams

<h3>Explanation:</h3>

From the question we are given;

  • Half-life of C-14 is 5730 years
  • Original mass of C-14 (N₀) = 150 grams
  • Time taken, t = 5000 years

We are required to determine the mass left after 5000 years

  • Using the formula;
  • N = No(1/2)^t/T​, where N is the remaining mass, N₀ is the original mass, t is the time taken and T is the half-life.

   t/T = 5000 yrs ÷ 5730 yrs

    = 0.873

N = 150 g ÷ 0.5^0.873

   = 150 g × 0.546

   = 81.9 g

Therefore, the mass of C-14 left after 5000 yrs is 81.9 g

5 0
3 years ago
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