The volume of a pond being studied for the effects of acid rain is 35 kiloliters (kL). There are 1,000 liters (L) in 1 kL and 1 x 10^6 <span>microliters (mL) in 1 L.
35 kL (1,000 L/ 1kL) (</span>1 x 10^6 microliters / 1 L) = 3.5 x 10^10 microliters<span>
The volume of this pond in microliters is </span><span>3.5 x 10^10 microliters</span>
Answer:
9.85
Explanation:
M1V1 =M2V2
6.20×v1= 0.470×0.130
v1 = ( 0.470 × 0.130 ) ÷ 6.20
v1 = 0.0098 L × 1000
V1 = 9.8 ml
You need the Avogadro's number. I can't remember exactly the calculation.
The reaction is:
Cl2 + 2 KBr --> 2 KCl + Br2
Moles of KCl is
n = m /M = 12 /74 = 0.16 mol
As, twice the moles of KCl is producing from 1 mol of chlorine
mole of Cl2 = 0.16 /2 = 0.08 mol
Mass of Cl2
m /70 = 0.08 = 5.6 g
Hence, 5.6 g mol Cl2 consumed to produce KCl
Answer:
Density of the He atom = 12.69 g/cm³
Explanation:
From the information given:
Since 1 mole of an atom = 6.022x 10²³ atoms)
1 atom of He = 

The volume can be determined as folows:
since the diameter of the He atom is approximately 0.10 nm
the radius of the He =
= 0.05 nm
Converting it into cm, we have:


Assuming that it is a sphere, the volume of a sphere is
= 
= 
= 
Finally, the density can be calcuated by using the formula :


D = 12.69 g/cm³
Density of the He atom = 12.69 g/cm³