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SVEN [57.7K]
2 years ago
7

Which statement accurately describes why air pressure decreases as altitude increases? As you increase altitude the temperature

difference between the layers of the atmosphere causes extreme winds and the air pressure in turn decreases. As you increase altitude, the air particles move around much more quickly because they have to travel further distances which decreases their pressure. As you increase altitude the temperature is increased and as you heat particles they spread further apart decreasing their pressure. As you increase altitude, Earth's gravity is not acting as greatly as when closer to Earth's surface so the weight of air molecules decrease, which also in turn decreases air pressure.
Chemistry
1 answer:
labwork [276]2 years ago
3 0

Answer:

The correct answer is " As you increase altitude, Earth's gravity is not acting as greatly as when closer to Earth's surface so the weight of air molecules decrease, which also in turn decreases air pressure."

Explanation:

As altitude increases air becomes rarefied. At higher altitudes there is less Earth's gravity acting on the air molecules than at areas close the earth surface. Air pressure is the weight of air acting per unit surface area. At higher altitudes as the weight of air decreases due to reduced gravitational pull the air pressure also decreases.

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The molecule with the largest dipole moment (a) co2 (b) h2o (c) ch4 (d) c2h4 (e) ph3
storchak [24]

The molecule with the largest dipole moment will be CH_{4}.

A dipole moment would be a unit used to describe how far apart two electrical charges are from one another. Dipole moments represent a type of vector. The direction could be from negative charge to positive charge, while the magnitude has been equal to the charge times the distance between most of the charges.

The polar bonds, of  CO_{2} as well as H_{2} O have chemical configurations where the polarity cancels, leaving no net dipole. Regardless of the molecule's shape, CH_{4} lacks a net dipole due to its non-polar links.

The molecule with the largest dipole moment will be CH_{4}.

Hence the correct answer will be option (c).

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3 0
2 years ago
A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 385.mg of oxalic acid H2
Vlada [557]

Answer:

The molarity of the sodium hydroxide solution is 0.0692 M

Explanation:

<u>Step 1: </u>Data given

Mass of H2C2O4 = 385 mg = 0.385 grams

volume = 250 mL = 0.250 L

Volume of NaOH = 123.7 mL = 0.1237 L

Molar mass H2C2O4 = 90.03 g/mol

<u>Step 2</u>: The balanced equation

2NaOH + H2C2O4 → Na2C2O4 + 2H2O

<u>Step 3:</u> Calculate moles H2C2O4

Moles H2C2O4 = mass H2C2O4 / molar mass H2C2O4

Moles H2C2O4 = 0.385 grams / 90.03 g/mol

Moles H2C2O4 = 0.00428 moles

<u>Step 4: </u>Calculate molarity of H2C2O4

Molarity H2C2O4 = moles / volume

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<u>Step 5:</u> Calculate molarity of NaOH

2*Ca*Va = n*Cb*Vb

⇒ with Ca = Molarity of H2C2O4 = 0.01712 M

⇒ Va = volume of H2C2O4 = 0.250 L

⇒Cb = molarity of NaOH = TO BE DETERMINED

⇒ Vb = volume of NaOH = 0.1237 L

Cb = (2*0.01712*0.250)/0.1237

Cb = 0.0691 M

The molarity of the sodium hydroxide solution is 0.0692 M

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