Answer:

Explanation:
MM: 2.016 17.03
N₂ + 3H₂ ⟶ 2NH3
m/g: 26.3
1. Theoretical yield
(a) Moles of H₂

(b) Moles of NH₃

(c) Theoretical yield of NH₃

(d) Percent yield

Answer:
Q = 3440Kj
Explanation:
Given data:
Mass of gold = 2kg
Latent heat of vaporization = 1720 Kj/Kg
Energy required to vaporize 2kg gold = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg
by putting values,
Q= 2kg × 1720 Kj/Kg
Q = 3440Kj
If you would draw the Lewis structures of these atoms, you would see that A has 2 electron pairs and 2 lone electrons (that can bond). For B you’d see that you only have 1 electron that can form a bond. This means that 1 atom of A (2 lone electrons) can bond with 2 atoms of B. To know the kind of bond you have to know wether or not there will be a ‘donation’ of an electron from one atom to another. This happens when the number of electrons on one atoms is equal to the number of electrons another atom needs to reach the noble gas structure. As you can see, this is not the case here. This means that you get an AB2 structure with covalent character.
I am a blacksmith, I would know this one. Alright... Aluminum, has a great shine to it, and it looks like silver... Same with tin, except aluminum is super shiny and sleek, while tin has a dull shine to it. Steel, is flat (color-wise), and it has a slight shine to it.
You can find what type of metal it is by color, shine, light reflectance, dullness, and several other properties. Hope I helped you! :)