The symbol equation for combustion of a hydrocarbon is shown below. What number will go before the oxygen reactant when

How many times do u have to run back and forth across a football field to be meter

Taya2010 [7]

You would have to run 100 kilometers across it once. Then you will have to run 10 meters across it because a football field is 110 meters according to the NFL’s website

7 0

3 years ago

Difference between---<br> soap and detergent

guapka [62]

Answer:

"Soaps are made from natural ingredients, such as plant oils (coconut, vegetable, palm, pine) or acids derived from animal fat. Detergents, on the other hand, are synthetic, man-made derivatives. While soap is limited in its applications, detergents can be formulated to include other ingredients for all sorts of cleaning purposes. Perhaps the most common and versatile of these ingredients are surfactants … surface active agents.

The main difference between soap and detergent is the ingredients. Soaps are made with biodegradable ingredients such as oils, lye and fats. ... Both clean clothes well, but detergents are more effective on stains and with brightening clothes. However, soap is kinder on the environment and skin. "

Hope this helps

Excerpt from textbook

8 0

2 years ago

Sea water contains roughly 158.0g of Nacl per liter. What is the molarity of sodium chloride in sea water?

IrinaK [193]

Molar mass NaCl = 58.5 g/mol

C = 158.0 g/L

Molarity = C / molar mass

M = 158.0 / 58.5

M = 2.7000 M

hope this helps!

6 0

3 years ago

Help thank you so so much!

Otrada [13]

Answer:

D is the answer to this problem

8 0

3 years ago

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

2 years ago