The symbol equation for combustion of a hydrocarbon is shown below. What number will go before the oxygen reactant when

The emission spectrums are known for the elements below. Line spectra for boron, lithium, hydrogen, helium, potassium and unknow

Montano1993 [528]

Answer:

E

Explanation:

8 0

2 years ago

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What is the gram formula mass of NazC03

kotykmax [81]

Answer:

84,007 g/mol

Explanation:

Molar mass of NazCO3 which is Sodium Bicarbonate (NaHCO₃) is 84,007 g/mol

7 0

3 years ago

Chlorine has two naturally occurring isotopes, 35C1 Gsotopic mass 34.9689 amu) and 370 (isotopic mass 36.9659 amu). If chlorine

Lilit [14]

Answer: The percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 75.77% and 24.23% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope be 'x'. So, fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope will be '1 - x'

For $_{17}^{35}\textrm{Cl}$ isotope:

Mass of $_{17}^{35}\textrm{Cl}$ isotope = 34.9689 amu

Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

For $_{17}^{37}\textrm{Cl}$ isotope:

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 36.9659 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

Average atomic mass of chlorine = 35.4527 amu

Putting values in equation 1, we get:

$35.4527=[(34.9689\times x)+(36.9659\times (1-x))]\\\\x=0.7577$

Percentage abundance of $_{17}^{35}\textrm{Cl}$ isotope = $0.7577\times 100=75.77\%$

Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.7577)=0.2423\times 100=24.23\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 75.77% and 24.23% respectively.

6 0

3 years ago

The Groups 1 and 2 on the periodic table contain what atom type?

Gemiola [76]

Metals is the right answer.

5 0

3 years ago

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At constant temperature, a sample of helium at 760. torr in a closed container was compressed from 5.00 l to 3.00 l, with no cha

Elden [556K]

At constant temperature and moles, the answer can simply becomes P1V1 = P2V2. The original sample is 760 torr and 5.00 l, and was then compressed to 3.00 l. (760 torr)(5.00 l ) = (3.00 l)(X torr), X = 1270 torr. The new pressure exerted by helium on its container is 1270 torr.

7 0

3 years ago