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Goryan [66]
3 years ago
15

C5h12 with one tertiary carbon

Chemistry
1 answer:
AfilCa [17]3 years ago
3 0

Answer:

See attached image.

Explanation:

Hello there!

In this case, according to the isomeric structure of hydrocarbons, it is possible to draw a five-carbon hydrocarbon with a tertiary carbon by keeping in mind these tertiary carbons are characterized by the presence of three bonds with carbon atoms.

In such a way, as shown on the attached image, the second carbon from left to right is tertiary because of the aforementioned, and also, the compound has five carbon atoms and twelve hydrogen atoms.

Best regards!

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A student who stresses too much about his grades has incorrectly named an organic compound 3-propylhexane.
Brums [2.3K]

Answer:

None of these.

The correct answer should be, 4-ethylheptane.

Explanation:

In naming Alkanes, the general rules apply:

I. Identify the longest continuous carbon chain and name it as the root or parent name.

II. Identify any side chains and add their names and positions as a prefix to the parent chain.

III. When there are more than one type of side chain, name them alphabetically.

IV. Use hyphens between numbers and letters and commas between numbers.

V. Number your side chains to obtain the lowest number combinations possible.

For the above question,

first, attempt drawing only the carbon skeleton, of 3-propylhexane thus,

C-C-C-C-C-C

|

C-C-C

The longest continuous carbon chain (numbering from the top right) is 7 carbon atoms, hence, parent or root name is heptane. The 2 carbon atoms (at top left) not numbered make up the alkyl group called ethyl and since they are attached to carbon number 4 of the numbered carbon atoms ( whether the numbering is from top right to bottom right or vice versa ), their position and name should be written as a prefix to the parent name. That is why the organic compound is named, 4-ethylheptane.

Please note that in drawing the carbon skeleton of 3-propylhexane, the name is the same even if you start placing the bottom 3 carbon atoms on the 3rd carbon (top) from the left or from the right because the numbering can start from any side to achieve the lowest number combinations of numbering common Alkanes.

7 0
3 years ago
Can salt dissolve in hydrogen peroxide? Pls help me
Genrish500 [490]

Answer:

Yes it can!!

Explanation:

Hydrogen peroxide mixed with sodium is known as oxygen bleach. Add water and the compound releases an oxygen molecule to help it lift mold and stains from the surface of natural materials.

3 0
3 years ago
An equilibrium mixture of CO, O2 and CO2 at a certain temperature contains 0.0010 M CO2 and 0.0025 M O2. At this temperature, Kc
pantera1 [17]

Answer:

5.35 *10^{-4}M

Explanation:

Equation for the reaction is as follows:

2CO_{(g)}      +      O_{2(g)}        ⇄       2CO_{2(g)}

By Applying the ICE Table; we have

                             2CO_{(g)}      +      O_{2(g)}        ⇄       2CO_{2(g)}

Initial                      x                  0.0025 M              0.0010 M

Change                  0                       0                            0

Equilibrium             x                  0.0025 M              0.0010 M

K_c =\frac{[CO_2]^2}{[CO]^2[O_2]}

Given that K_c = 1.4*10^2 ; Then:

1.4 *10^2 = \frac{(0.001)^2}{(x)^2(0.025)}

1.4 *10^2*0.025 = \frac{(0.001)^2}{(x)^2}

3.5 =( \frac{(0.001)}{(x)})^2

\sqrt {3.5} = \sqrt {( \frac{(0.001)}{(x)} )^2}

1.87=\frac{(0.001)}{(x)}

(x)= \frac{(0.001)}{1.87 }

x = 5.35 *10^{-4}M

∴ The equilibrium concentration of CO = x = 5.35 *10^{-4}M

7 0
4 years ago
If two gases A and B are at the same temperature and pressure, the ratio of their effusion rates is
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If the gases are at the same temperature and pressure, the ratio of their effusion rates is directly proportional to the ratio of the square roots of their molar masses:

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

Where

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  • M₁ and M₂ are the molar masses of the two gas

From the Graham's law equation, we can see that the ratio of the rates of effusion of the two gases is directly proportional to the square root of their molar masses

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

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7 0
3 years ago
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