Basically y would be whatever the number x is times 2, so -2 to the second power is -4, -1 to the second power is -1, 0 to the second power is 0, 1 to the second power is 1 and 2 to the second power is 4. now all you have to do is graph those points and you’re good!
956.25 is the answer
Because 1 bottle is 212.5 grams of sugar you can just multiply that by 4.5 because there are 4 bottles and a half of a bottle
Answer:
C
Step-by-step explanation:
y-3=5(x-2) (rearrange this to be in slope- intercept from) (add 3 to both sides)
y = 5(x-2) + 3 (distribute parentheses)
y = x(5) - 2(5) + 3
y = 5x -10 + 3
y = 5x - 7
recall that for a line with gradient m, the gradient of the perpendicular line will be - (1/m)
hence in our case, our gradient of the original line is 5, hence the gradient of the perpendicular line is -1/5
From the choices, the only one that is consistent with this is C
i.e choice C:
5y + x = 25
5y = -x + 25
y = -(1/5) x + 5 ===> gradient of -1/5
Subtract normally as if 32.6 is 316 and 1.9 is 19. Then you move the decimal point two places to the left of the answer
the answer is 29.7
Answer:
1,215 Superscript one-fifth x
Step-by-step explanation:
Given:
The expression to simplify is given as:
![(\sqrt[5]{1215})^x](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7B1215%7D%29%5Ex)
We know that,
![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Here, 
So, ![\sqrt[5]{1215} = 1215^{\frac{1}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B1215%7D%20%3D%201215%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D)
So, the above expression becomes:
![(\sqrt[5]{1215})^x = (1215^{\frac{1}{5}})^x](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7B1215%7D%29%5Ex%20%3D%20%281215%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5Ex)
Now, using the law of indices 
Here, 
So, the expression is finally simplified to;
Therefore, the second option is the correct one.
= 1,215 Superscript one-fifth x
