1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex_Xolod [135]
3 years ago
14

Help please!

Mathematics
1 answer:
Nina [5.8K]3 years ago
3 0

Answer:

a: f= 24y−17 /3y−1

b: x=−23

Step-by-step explanation:

You might be interested in
Melvin and Frank caught a lizard in their backyard. Its body is 178 long, and its tail
damaskus [11]

Answer:

286 cm.

Step-by-step explanation:

You add up the two sections, since it is implied that there are no intersection between the two lengths.

178 + 108 = 286 cm.

3 0
3 years ago
In which type of economy does the government control all of the factors of production? A. mixed B. market C. command D. traditio
melomori [17]

Answer:

In a command economy, the government controls major aspects of economic production. The government decides the means of production and owns the industries that produce goods and services for the public

Step-by-step explanation:

hope this helps!

7 0
3 years ago
Brainliest If Correct
natta225 [31]

Answer:

52

Step-by-step explanation:

Messed up, 292+52=240, I hope it’s correct for you,  I have Alzheimer, I hope is correct for you!

8 0
2 years ago
Determine the first four terms of the sequence in which the nth term is...
Anon25 [30]

Answer:

1/5, 1/6, 1/7, 1/8

Step-by-step explanation:

The formula for the sequence is (n+3)!/ (n+4)!

The first terms uses n=1

a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5


The first terms uses n=2

a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6


The first terms uses n=3

a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7


The first terms uses n=4

a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8

7 0
3 years ago
Read 2 more answers
There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student
Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0
3 years ago
Other questions:
  • 1. 7 2/3 + 2 7/12
    15·1 answer
  • What is 62.713 rounded to the nearest hundredth?
    9·1 answer
  • mabel received 120 of the most popular beads for her birthday. there were 4 packages. how many beads per package were ther.
    9·1 answer
  • See attached photo. Please Help ASAP and Explain
    6·1 answer
  • If you are also able to explain this please do! I'd greatly appreciate it!
    5·2 answers
  • I will upvote and give brainliest answer
    11·1 answer
  • Another one of these, god help me
    15·2 answers
  • Please help this is due today!!
    15·1 answer
  • Sheila buys some boxes of pens, with 20 pens in each box.
    10·2 answers
  • Geroge is bringing garonla bars and apples for his classmate at school apples cost 0.75 each qnd garonla bars cost 0.15 each ger
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!