1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nasty-shy [4]
2 years ago
5

Vanillin (used to flavour vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

amount. The threshold limit is 2.0 x 10-11 gram per liter of air. If the current price of 50 g of vanillin is $112, determine the cost to supply enough vanillin so that the aroma could be detectable in a large aircraft hangar of volume 5.0 x 107 ft3.
Chemistry
1 answer:
Rudiy272 years ago
6 0

Answer:

The cost is $0.063.

Explanation:

First, we need to express the volume of the hangar in liters. We know that 1 ft³ = 28.31 L, so using proportions:

5.0 \times 10^{7} ft^{3} .\frac{28.31L}{1ft^{3} } =1.4 \times 10^{9} L

The amount of vanillin required would be:

1.4 \times 10^{9} L.\frac{2.0\times 10^{-11}g }{1L} =0.028g

Finally, the price for such amount of vanillin is:

0.028g.\frac{ \textdollar 112}{50g}=  \textdollar 0.063

You might be interested in
A chemist titrates 130.0mL of a 0.4248 M lidocaine (C14H21NONH) solution with 0.4429 M HBr solution at 25 degree C . Calculate t
jeka57 [31]

Answer:

pH = 3.36

Explanation:

Lidocaine is a weak base to be titrated with the strong acid HBr, therefore at equivalence point we wil have the protonated lidocaine weak conjugate acid of lidocaine which will drive the pH.

Thus to solve the question we will need to calculate the concentration of this weak acid at equivalence point.

Molarity = mol /V ∴ mol = V x M

mol lidocaine = (130 mL/1000 mL/L) x 0.4248 mol/L = 0.0552 mol

The volume of 0.4429 M HBr required to neutralize this 0.0552 mol is

0.0552 mol x  (1L / 0.4429mol) = 0.125 L

Total volume at equivalence is  initial volume lidocaine + volume HBr added

0 .130 L +0.125 L = 0.255L

and the concentration of protonated lidocaine at the end of the titration will be

0.0552 mol / 0.255 L = 0.22M

Now to calculate the pH we setup our customary ICE table for  weak acids for the equilibria:

protonated lidocaine + H₂O   ⇆  lidocaine + H₃O⁺

                      protonated lidocaine          lidocaine        H₃O⁺

Initial(M)               0.22                                       0                  0

Change                   -x                                      +x                 +x

Equilibrium          0.22 - x                                  x                    x

We know for this equilibrium

Ka = [Lidocaine] [H₃O⁺] / [protonaded Lidocaine] =  x² / ( 0.22 - x )

The Ka can be calculated from the given pKb for lidocaine

Kb = antilog( - 7.94 ) = 1.15 x 10⁻⁸

Ka = Kw / Kb = 10⁻¹⁴ / 1.15 x 10⁻⁸  = 8.71 x 10⁻⁷

Since Ka is very small we can make the approximation 0.22  - x  ≈ 0.22

and solve for x. The pH  will then  be the negative log of this value.

8.71 x 10⁻⁷  = x² / 0.22 ⇒ x = √(/ 8.71 X 10⁻⁷ x 0.22) = 4.38 x 10⁻⁴

( Indeed our approximation checks since 4.38 x 10⁻⁴ is just 0.2 % of 0.22 )

pH = - log ( 4.4x 10⁻⁴) = 3.36

3 0
3 years ago
An oxybromate compound, kbrox, where x is unknown, is analyzed and found to contain 43.66 % br.
aniked [119]

Answer is: an oxybromate compound is KBrO₄ (x = 4).

ω(Br) = 43.66% ÷ 100%.

ω(Br) = 0.4366; mass percentage of bromine.

If we take 100 grams of compound:

m(Br) = ω(Br) · 100 g.

m(Br) = 0.4366 · 100 g.

m(Br) = 43.66 g; mass of bromine.

n(Br) = m(Br) ÷ M(Br).

n(Br) = 43.66 g ÷ 79.9 g/mol,

n(Br) = 0.55 mol; amoun of bromine.

From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).

m(K) = 0.55 mol · 39.1 g/mol.

m(K) = 21.365 g; mass of potassium in the compound.

m(O) = 100 g - 21.365 g - 43.66 g.

m(O) =34.97 g; mass of oxygen.

n(O) = 34.97 g ÷ 16 g/mol.

n(O) = 2.185 mol.

n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.

n(K) : n(Br) : n(O) = 1 : 1 : 4.

6 0
3 years ago
What does a fluorine ion have in common with a neon and a sodium ion
DanielleElmas [232]
The atomic number (Z) of the 3 elements F, Ne, and Na, are 9, 10, and 11.

Explanation:

Now Z refers to the number of protons in the element's nucleus, and protons are POSITIVELY charged particles. So a fluoride ion, F−, has 10 electrons rather than 9 (why?), a neutral neon atom has 10 electrons, and a sodium ion, Na+, also has 10 electrons (why?).

So the 3 species are ISOELECTRONIC; they possess the same number of electrons. 

You should look at the Periodic Table to confirm the electron number. Elements are (usually) electrically neutral (sometimes they can be ionic if they have lost or gained electrons). If there are 10 positively charged protons in the nucleus, there are NECESSARILY 10 electrons associated with the NEUTRAL atom. I don't know WHY I am capitalizing certain WORDS.

You might ask why sodium will form a positive ion, Na+, whereas F forms a negative ion, F−. This again is a Periodic phenomenon, and explicable on the basis of the electronic structure that the Table formalizes.

Neutral metals tend to be electron-rich species, which have 1 or more electrons in a valence shell remote from the nuclear charge. On the other hand, neutral non-metals have valence electrons in incomplete shells, that do not effectively shield the nuclear charge. The demonstrable consequence is that metals lose electrons to form positive ions, whereas non-metals gain electrons to form negative ions.

6 0
3 years ago
What is the definition of the word: Property (the scientific definition A makes up matter; makes up the world around us B an obj
IRISSAK [1]

Answer:

i feel like the answer is A

4 0
3 years ago
Select the correct answer.
Elina [12.6K]

Answer:

CU

Explanation:

Cu is the correct answer if I'm correct

4 0
2 years ago
Other questions:
  • [40 Points]
    13·1 answer
  • Calculate the mass of CaCl2 ( formula wt. = 110.99) thatshould
    14·1 answer
  • Unknown element has two isotopes. Isotope A has a mass of 34 amu and abundance of 52%, isotope B has a mass of 33 amu and abunda
    12·1 answer
  • The temperature of evaporation is much higher for water than for alcohol. Without knowing more about the chemistry of alcohol, w
    12·1 answer
  • How many atoms are in 3.2 moles of chromium?
    14·1 answer
  • Our sun is a big ball of ______ & _______ gases
    8·2 answers
  • Help me plzzzzz ASAP!!!!!
    13·1 answer
  • Write the cations and anions present in NaCl​
    5·1 answer
  • 63.15 mL of calcium hydroxide is required to titrate 18.9 mL of a 0.200 M H3PO4 solution. What is the molarity of the basic solu
    8·1 answer
  • The heaviest known alkaline earth metal is radium, atomic number 88.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!