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nasty-shy [4]
2 years ago
5

Vanillin (used to flavour vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

amount. The threshold limit is 2.0 x 10-11 gram per liter of air. If the current price of 50 g of vanillin is $112, determine the cost to supply enough vanillin so that the aroma could be detectable in a large aircraft hangar of volume 5.0 x 107 ft3.
Chemistry
1 answer:
Rudiy272 years ago
6 0

Answer:

The cost is $0.063.

Explanation:

First, we need to express the volume of the hangar in liters. We know that 1 ft³ = 28.31 L, so using proportions:

5.0 \times 10^{7} ft^{3} .\frac{28.31L}{1ft^{3} } =1.4 \times 10^{9} L

The amount of vanillin required would be:

1.4 \times 10^{9} L.\frac{2.0\times 10^{-11}g }{1L} =0.028g

Finally, the price for such amount of vanillin is:

0.028g.\frac{ \textdollar 112}{50g}=  \textdollar 0.063

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What is the boiling point of 0.464 m lactose in water? (Kb of water = 0.512 oC/m). Enter your answer to 3 decimal places.
kirill [66]

Answer:

Boiling point for the solution is 100.237°C

Explanation:

We must apply colligative property of boiling point elevation

T° boiling solution - T° boiling pure solvent = Kb . m

m = molalilty (a given data)

Kb = Ebulloscopic constant (a given data)

We know that water boils at 100°C so let's replace the information in the formula.

T° boiling solution - 100°C = 0.512 °C/m . 0.464 m

T° boiliing solution = 0.512 °C/m . 0.464 m + 100°C → 100.237 °C

3 0
2 years ago
A student is adding DI water to a volumetric flask to make a 50% solution. Unfortunately, he was not paying attention and filled
dalvyx [7]

Answer:

His results will be skewed because there was more water than stock solution. Which would cause the percentage solution to be less than 50% therefore the density would be less than the actual value.

Explanation:

The solution will have percentage less than that of 50%. Therefore the density would be less than the actual value.

Suppose there should be 50 mL of the solution, and he added 60 mL. So 10 mL of the solution is added more.

Suppose the mass of the solute is m.

Originally, the density is = $\frac{m}{50}$     \left(\frac{\text{mass}}{\text{volume}}\right)

Now after adding extra 10 mL , the density becomes $\frac{m}{60}$.

Therefore, $\frac{m}{50}>\frac{m}{60}$

So the density decreases when we add more solution.

4 0
3 years ago
You are taking a 578.23 mile trip to visit your grandparents. What is the distance of this trip in kilometers?
Tamiku [17]
578.23 miles = 930.6 kilometers (Rounded up to the nearest tenth.)
5 0
3 years ago
An atom has 14 protons, 16 neutrons, and 14 electrons. What is its mass number?
Andrews [41]

The answer is 30.

Explanation:

The total number of protons and neutrons in a nucleus is called mass number. So 14 proton plus 16 neutron is = 30 mass number.

6 0
3 years ago
Look at this balanced chemical reaction: N2 + 3H2 2NH3
stepladder [879]

Answer: A mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.

Explanation:

Given: Volume = 450 L

Temperature = 450 K

Pressure = 300 atm

Using ideal gas equation, moles of nitrogen are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = tempertaure

Substitute values into the above formula as follows.

PV = nRT\\300 atm \times 450 L = n \times 0.0821 L atm/mol K \times 450 K\\n = \frac{135000}{36.945}\\= 3654.08 mol

According to the given equation, 1 mole of nitrogen forms 2 moles of ammonia. So, moles of ammonia formed by 3654.08 moles of nitrogen is as follows.

2 \times 3654.08 mol\\= 7308.16 mol

As moles is the mass of substance divided by its molar mass. So, mass of ammonia (molar mass = 17.03 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\7308.16 = \frac{mass}{17.03 g/mol}\\mass = 124457.96 g

Thus, we can conclude that a mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.

8 0
3 years ago
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