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olga2289 [7]
3 years ago
6

Pertain to the following class, Point:

Chemistry
1 answer:
Anton [14]3 years ago
5 0

Answer:

Explanation:

b = 0;

this (x, y);

this(0, 0);

x = a;

y = b;

a =

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C= 51.89% H= 9.82% Br=38.29%
maks197457 [2]

Answer:

a

Explanation:

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Within a single molecule of water, two hydrogen bonds are bonded to a single oxygen atom by_______.However when there are multip
Gnesinka [82]

Answer:

covalent bonding, hydrogen bonding

Explanation:

<u>The molecular formula of water is H_2O in which the two hydrogen atoms are connected to the oxygen atom via covalent bonds which means that the electrons are shared in the bond.</u>

Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.

Partially positive end of the hydrogen atom is attracted to partially negative end of these atoms which is present in another molecule. It is strong force of attraction between the molecules.

<u>Thus, when multiple water molecules are there, there are connected by hydrogen bonding.</u>

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Examine the picture below and read the description.
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Explanation:

<h3>hahahahaha Hindi ko alam thanks nalang sa point</h3>
5 0
2 years ago
Please help :) Explain why a change in the position of a substituent group can, but does not always, result in a different compo
Lady bird [3.3K]
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3 years ago
Given that sodium chloride is 39.0% sodium by mass, how many grams of sodium chloride are needed to have 100.mg of Na present? G
seraphim [82]

<u>Answer:</u> The mass of sodium chloride solution present is 0.256 grams.

<u>Explanation:</u>

We are given:

39.0 % of sodium in sodium chloride solution

This means that 39.0 grams of sodium is present in 100 grams of sodium chloride solution

Mass of sodium given = 100 mg = 0.1 g     (Conversion factor:  1 g = 1000 mg)

Applying unitary method:

If 39 grams of sodium metal is present in 100 grams of sodium chloride solution

So, if 0.1 grams of sodium metal will be present in = \frac{100}{39}\times 0.1=0.256g of sodium chloride solution.

Hence, the mass of sodium chloride solution present is 0.256 grams.

8 0
3 years ago
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