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Svetllana [295]
3 years ago
8

150 words describing Bohr’s model, and the fundamental principles behind it. Also, explain how Bohr’s model is different from Ru

therford’s model.
Chemistry
1 answer:
luda_lava [24]3 years ago
8 0
Bohr's model is different from Rutherford's model by Bohr's model has 150 words , fundamental principles. also Rutherford's model does not have 150 words and fundamental principles. <span />
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How many grams of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O?
shepuryov [24]

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity = \frac{no. of moles}{Volume (in L) of solution}

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

           molarity = \frac{no. of moles}{Volume of solution in liter}

            0.0800 M = \frac{no. of moles}{0.05 L}

            no. of moles = 1.6 mol

Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

                No. of moles = \frac{mass in grams}{molar mass}

             mass in grams = no. of moles \times molar mass of CuSO_{4}.5H_{2}O

                                       = 1.6 mol \times 249.68 g/mol

                                       = 399.488 g

Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

4 0
3 years ago
What is similar about the outer shell of electrons in the alkali metals family
Nadusha1986 [10]

Answer:

1 electron

Explanation:

These metals have a single electron in the outer shell

4 0
3 years ago
How many molecules make up 8.41 moles of Ca2(SO3)?
sammy [17]

Answer:

<h3>5.06282 × 10²⁴ molecules</h3>

Explanation:

The number of molecules of Ca2(SO3) can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 8.41 × 6.02 × 10²³

We have the final answer as

<h3>5.06282 × 10²⁴ molecules</h3>

Hope this helps you

3 0
2 years ago
What mass of O2, in grams, is required to completely react with 0.025 g C3H8?
8090 [49]
2C3H8+ 702--->6CO2+8H20
FROM  Equation  above  2  moles of C3H8    reacted with  7  moles  of oxygen  to  form   6  moles of  c02 plus  8  molesof  H2O  
the  moles  of  c3H8  reacted is = MASS/ R.F.M
THE  R.F.M =48+8=44
Number  of  moles is  hence 0.025/44=5.68x10^-4
 
since  ratio  of  C3H8  to   O2 is  2:7  Therefore moles of   O2  reacted  is  1.989 x10^-3
mass= r.f.m  x  number  of  moles
(1.989x10^-3)   x  32 =0.064g
6 0
3 years ago
Pls help if you only know the correct answer! Thanks!!
Likurg_2 [28]

Answer:

1. H=2, O=1

2. H=4, O=2

3. C=1, O=1

4.

a. reactants C=1, O=2

b. products C=1, O=2

5.

a. reactants H=4, O=2

b. products H=4, O=2

6

a. reactants C=1, O=1, H=4

b. products C=1, O=1, H=4

4 0
2 years ago
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