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zubka84 [21]
2 years ago
8

Answer these questions :) please

Chemistry
1 answer:
3241004551 [841]2 years ago
4 0
They have built farming terraces along the mountain slopes.
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Can someone help me Balance chemical equations please
horrorfan [7]
2NaClO3 = 2NaCl + 3O2
Hopes this helps <33
4 0
2 years ago
2Na + CaF2à 2NaF + Ca is an example of a _________ chemical reaction.
marusya05 [52]
<span>2 Na + CaF</span>₂<span> = 2 NaF + Ca

is an example of a </span>single- replacement

answer D

hope this helps!
6 0
3 years ago
(b) difference between metalloids and alloys​
blsea [12.9K]

Answer:

<u>Metalloid -</u>

A metalloid is a chemical element with properties intermediate between those of typical metals and nonmetals

<u>Alloy</u> -

An alloy is a mixture of metals or a mixture of a metal and another element. Alloys are defined by a metallic bonding character.

5 0
2 years ago
Read 2 more answers
Cho m gam FeO tác dụng hết với dung dịch H2SO4, thu được 200 ml dung dịch FeSO4 1M. Giá trị của m là
BaLLatris [955]

<u>Answer:</u> The mass of FeO required is 14.37 g

<u>Explanation:</u>

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume}} ......(1)

We are given:  

Molarity of iron (II) sulfate = 1 M

Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

\text{Moles of }FeSO_4=(1mol/L\times 0.200L)=0.200mol

The chemical equation for the reaction of FeO with sulfuric acid follows:

FeO+H_2SO_4\rightarrow FeSO_4+H_2O

By stoichiometry of the reaction:

If 1 mole of iron (II) sulfate is produced by 1 mole of FeO

So, 0.200 moles of iron (II) sulfate will produce = \frac{1}{1}\times 0.200=0.200mol of FeO

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We know, molar mass of FeO = 71.84 g/mol

Putting values in above equation, we get:

\text{Mass of }FeO=(0.200mol\times 71.84g/mol)=14.37g

Hence, the mass of FeO required is 14.37 g

4 0
3 years ago
A chemist makes 940. mL of sodium carbonate (Na_2CO_3) working solution by adding distilled water to 200. mL of a 0.171 m stock
Alexxandr [17]

Answer:

The answer is 0.0698 M

Explanation:

The concentration was prepared by a serial dilution method.

The formula for the preparation I M1V1 = M2V2

M1= the concentration of the stock solution = 0.171 M

V1= volume of the stock solution taken = 200 mL

M2 = the concentration produced

V2 = the volume of the solution produced = 940 mL

Substitute these values in the formula

0.171 × 200 = 490 × M2

34.2 = 490 × M2

Make M2 the subject of the formula

M2 = 34.2/490

M2 = 0.069795

M2 = 0.0698 M ( 3 s.f)

The concentration of the Chemist's working solution to 3 significant figures is 0.0698M

6 0
3 years ago
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