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saw5 [17]
3 years ago
8

A student observed tiny dots moving about when exploring a drop of pond water. At 400x magnification, the student recognized the

organisms as paramecia. Paramecia are examples of organisms.
Chemistry
1 answer:
igomit [66]3 years ago
5 0

Paramecia are examples of unicellular organisms. They are protists.

<h3>Protists</h3>

Protists are eukaryotic unicellular (single-celled) organisms that do not fit into any other category.

Paramecia are protists microorganisms generally found in aquatic habitats (e.g., a pond).

Paramecia generally have an oblong shape and they are covered with tiny structures known as cilia (for motion).

Learn more about protists here:

brainly.com/question/12206236

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Determine the empirical formula of a compound having the following percent composition by mass: K: 24.74%; Mn: 34.76%; O: 40.50%
Dovator [93]

<u>Answer:</u> The empirical formula of the compound is KMnO_4

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Let the mass of the compound be 100 g

Given values:

% of K = 24.7%

% of Mn = 34.76%

% of O = 40.50%

Mass of K = 24.7 g

Mass of Mn = 34.76 g

Mass of O = 40.50 g

To calculate the empirical formula of a compound, few steps need to be followed:

  • <u>Step 1:</u> Calculating the number of moles of each element

We know:

Molar mass of K = 39.10 g/mol

Molar mass of Mn = 54.94 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of K}=\frac{24.7g}{39.10g/mol}=0.632 mol

\text{Moles of Mn}=\frac{34.76g}{54.94g/mol}=0.633 mol

\text{Moles of O}=\frac{40.50g}{16g/mol}=2.53 mol

  • <u>Step 2:</u> Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 0.632 moles

\text{Mole fraction of K}=\frac{0.632}{0.632}=1

\text{Mole fraction of Mn}=\frac{0.633}{0.632}=1

\text{Mole fraction of O}=\frac{2.53}{0.632}=4

  • <u>Step 3:</u> Writing the mole fraction as the subscripts of each of the element

The empirical formula of the compound becomes K_1Mn_1O_4=KMnO_4

Hence, the empirical formula of the compound is KMnO_4

4 0
3 years ago
The use of thermite for welding produces an
Sveta_85 [38]

Answer:

C. grinding the reactants into finer grains

Explanation: I just took the assignment.

8 0
3 years ago
Water is a ______ molecule and the bond between the h-o is a __ ______ bond.
omeli [17]

Answer: polar molocule

Explanation:

8 0
3 years ago
What happens when you put on deodorant? does it absorb heat and give off thermal energy
Lunna [17]
It absorbs heat and give off thermal energy just saying i think its right
3 0
4 years ago
What is the concentration of hydronium ion in a 0.121 M HCl solution?
kogti [31]

Answer:

C) 0.121 M

Explanation:

HCl + H₂O = H₃O⁺ + OH⁻

.121M              .121M

HCl is a strong acid . It will dissociate almost 100 % so the concentration of acid and hydronium ion formed will be equal . It is to be noted that hydronium ion is formed due to association of H⁺ and H₂O . H⁺ is formed due to ionisation of HCl .

So concentrtion of hydronium ion ( H₃O⁺ ) will be .121 M.

7 0
3 years ago
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