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saw5 [17]
2 years ago
8

A student observed tiny dots moving about when exploring a drop of pond water. At 400x magnification, the student recognized the

organisms as paramecia. Paramecia are examples of organisms.
Chemistry
1 answer:
igomit [66]2 years ago
5 0

Paramecia are examples of unicellular organisms. They are protists.

<h3>Protists</h3>

Protists are eukaryotic unicellular (single-celled) organisms that do not fit into any other category.

Paramecia are protists microorganisms generally found in aquatic habitats (e.g., a pond).

Paramecia generally have an oblong shape and they are covered with tiny structures known as cilia (for motion).

Learn more about protists here:

brainly.com/question/12206236

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Is melting sugar a chemical or physical change? Please provide an explanation
liraira [26]

Answer:

Hola Amigo! Here's Ur Answer :D

Explanation:

The chemical reaction we are most familiar with is that of melting: sugar decomposes at a temperature ranging between 184 and 186°C. This is a very recent discovery we owe to a team of researchers in Illinois. Basically, when we heat sucrose gently, this produces a phenomenon known as “ apparent melting ”.

Happy to Help! :D

3 0
3 years ago
Read 2 more answers
How many formula units of sodium chloride (NaCl) may theoretically be produced from 13.0 g FeCl3?
algol [13]

Answer:

1.445\times 10^{23} formula units of sodium chloride can be formed from 13.0 gram of ferric chloride.

Explanation:

Mass of ferric chloride = 13.0 g

Moles of ferric chloride = \frac{13.0 g}{162.5 g/mol}=0.08 mol

1 mole of ferric chloride has three moles of chloride ions.Then 0.08 moles of ferric chloride will have :

3\times 0.08 mol=0.24 mol of chloride

Na^++Cl^-\rightarrow NaCl

1 mole of sodium ion reacts with 1 mole of chloride ion to form 1 mole of NaCl. Then 0.24 moles of chloride ion will give:

\frac{1}{1}\times 0.24 mol=0.24 mol of NaCl

1 mole = N_A=6.022\times 10^{23} molecules/ atoms

Number of NaCl molecules in 0.24 moles :

=6.022\times 10^{23}\times 0.24=1.445\times 10^{23} molecules

1.445\times 10^{23} formula units of sodium chloride can be formed from 13.0 gram of ferric chloride.

4 0
3 years ago
Help meh put this inkshsbj
galina1969 [7]
What do you need help on?
7 0
3 years ago
What is the significance of the repeated word “inconceivable”?<br> HELP MEEEEE !
Elanso [62]

Answer:

not capable of being imagined or grasped mentally; unbelievable.

Explanation:

not capable of being imagined or grasped mentally; unbelievable.

8 0
3 years ago
Arrange the following aqueous solutions in order of increasing boiling point temperature (lowest to highest temperature, with 1
Elanso [62]

Answer:

0.20 m glucose < 0.40 m NaCl < 0.30 m BaCl2 < 0.50 m Na2SO4.

Explanation:

Step 1: Data given

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation =  Shows how much the boiling point increases

⇒i = the van't Hoff factor: Says in how many particles the compound will dissociate

⇒ Since all are aqueous solutions Kb for all solutions is the same (0.512 °C/m)

⇒m = the molality

Step 2:

0.20 m glucose

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation = TO BE DETERMINED

⇒i = the van't Hoff factor for glucose = 1

⇒ Kb = 0.512 °C/m

⇒m = 0.20 m

ΔT = 1*0.512 * 0.20

<u>ΔT = 0.1024 °C</u>

0.30 m BaCl2

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation = TO BE DETERMINED

⇒i = the van't Hoff factor for BaCl2 = Ba^2+ + 2Cl- : i = 3

⇒ Kb = 0.512 °C/m

⇒m = 0.30 m

ΔT = 3*0.512 * 0.30

<u>ΔT = 0.4608 °C</u>

0.40 m NaCl

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation = TO BE DETERMINED

⇒i = the van't Hoff factor for NaCl = Na+ + Cl- : i = 2

⇒ Kb = 0.512 °C/m

⇒m = 0.40 m

ΔT = 2*0.512 * 0.40

<u>ΔT = 0.4096 °C</u>

0.50 m Na2SO4.

ΔT = i*Kb*m

⇒ΔT = the boiling point elevation = TO BE DETERMINED

⇒i = the van't Hoff factor for Na2SO4 = 2Na+ + SO4^2- : i =3

⇒ Kb = 0.512 °C/m

⇒m = 0.50 m

ΔT = 3*0.512 * 0.50

<u>ΔT = 0.768 °C</u>

0.20 m glucose < 0.40 m NaCl < 0.30 m BaCl2 < 0.50 m Na2SO4.

8 0
3 years ago
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