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saw5 [17]
2 years ago
8

A student observed tiny dots moving about when exploring a drop of pond water. At 400x magnification, the student recognized the

organisms as paramecia. Paramecia are examples of organisms.
Chemistry
1 answer:
igomit [66]2 years ago
5 0

Paramecia are examples of unicellular organisms. They are protists.

<h3>Protists</h3>

Protists are eukaryotic unicellular (single-celled) organisms that do not fit into any other category.

Paramecia are protists microorganisms generally found in aquatic habitats (e.g., a pond).

Paramecia generally have an oblong shape and they are covered with tiny structures known as cilia (for motion).

Learn more about protists here:

brainly.com/question/12206236

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How might the research described in the article help address the food supply for a growing population?
Elodia [21]

I would say it’s helps with basic reproduction and let’s animals develop more.

8 0
3 years ago
1. 100gm of a 55% (M/M) nitric acid solution is to be diluted to 20% (M/M) nitric acid.
stealth61 [152]

Answer:

The volume of water to be added is 0.175 liters of water

Explanation:

The given concentration of the nitric acid = 55% (M/M)

The mass of the nitric acid solution = 100 gm

The concentration solution is to diluted to = 20% (M/M)

The 100 g 55%(M/M) nitric acid solution gives 55g nitric acid in 100 g of solution

Therefore, to have 20% (M/M) nitric acid solution with the 55 g nitric acid, we get

Let "x" represent the volume of the resulting solution, we have;

20% of x = 55 g of nitric acid

∴ 20/100 × x = 55 g

x = 55 g × 100/20 =  275 g

The mass of extra water to be added = The mass of the 20%(M/M) solution solution of nitric acid - The current mass of the 55%(M/M) solution of nitric acid

The mass of extra water to be added = 275 g - 100 g = 175 g

Volume = Mass/Density

The density of water ≈ 1 g/ml

∴ The volume of water to be added that gives 175 g of water =  175 g/(1 g/ml) = 175 ml. = 0.175 l

The volume of water to be added = 0.175 liters of water.

3 0
3 years ago
What is the noble-gas configuration for As​
jasenka [17]

Answer:

Noble gas Electronic configuration of arsenic:

As₃₃ = [Ar] 3d¹⁰ 4s² 4p³

Explanation:

Arsenic is metalloid.

Its atomic number is 33.

Its atomic mass is 75 amu.

Its symbol is As.

It is usually present in combine with sulfur and metals.

it is used in bronzing.

It is also used for hardening.

Electronic configuration:

As₃₃ = Is² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p³

Noble gas Electronic configuration:

As₃₃ = [Ar] 3d¹⁰ 4s² 4p³

Noble gas electronic configuration is shortest electronic configuration by using the noble gas elements full octet electronic configuration.

3 0
3 years ago
What happens to the temperature of the remaining liquid when some of the liquid evaporates
Dovator [93]
Turns into vapor. not all of the molecules are liquid have the same energy
7 0
3 years ago
Which statement is true about water molecules?
Arte-miy333 [17]
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4 0
3 years ago
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