Answer:
Explanation:
Given
N0 = 20kg (original substance)
decay constant λ = 0.179/sec
time t = 300s
We are to find N(t)
Using the formula;
n(t) = N0e^-λt
Substitute the given values
N(t) = 20e^-(0.179)(300)
N(t) = 20e^(-53.7)
N(t) = 20(4.7885)
N(t) =143.055
To know how much of the original material that is active, we will find N(t)/N0 = 143.055/20 = 7.152
About 7 times the original material is still radioactive
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Answer:
under
Explanation:
We know that F = ma,
or, a = F/m
or, a = 120/30 (because, Force = 120 N and mass = 30 kg)
or a = 4m/s^2
Hence, the acceleration of the object is 4 meter per second squared.
They all have to do something with physics?
Answer:
447 K
Explanation:
25 C = 25 + 273 = 298 K
Assuming ideal gas, we can apply the ideal gas law
Since pressure is tripled, then 
. Volume is halved, then 
