Answer:
- In general, polar solutes are most soluble in highly polar solvents.
Explanation:
The general rule is "like dissolves like" which means that <em>polar solvents </em>dissolve polar (or ionic) <em>solutes</em> and <em>non-polar solvents</em> dissolve non-polar solutes.
In order for a solvent dissolve a solute, the strength of the interacttion (force) between the solute and the solvent units (atoms, molecules, or ions) must be stronger than the strength of the forces that keep together he particles of the pure substances (known as intermolecular forces).
Since the nature of the interactions between the units are electrostatic, the more polar is the solvent the better it will be able to attract and surround the solute particles, keeping them separated and in solution. That mechanism explains why polar solutes will be most soluble in highly polar solvents.
Answer:
285g of fluorine
Explanation:
To solve this problem we need to find the mass of Freon in grams. Then, with its molar mass we can find moles of freon and, as 1 mole of Freon, CCl₂F₂, contains 2 moles of fluorine, we can find moles of fluorine and its mass:
<em>Mass Freon:</em>
<em>2.00lbs * (454g / 1lb) = </em>908g of Freon
<em>Moles freon -Molar mass: 120.91g/mol- and moles of fluorine:</em>
908g of Freon * (1mol / 120.91g) =
7.5 moles of freon * (2moles Fluorine / mole Freon): 15 moles of fluorine
<em>Mass fluorine -Atomic mass: 19g/mol-:</em>
15 moles F * (19g / mol) =
<h3>285g of fluorine</h3>
Answer;
FeSO4 (aq) + H2 (g)
Explanation;
The reaction between iron and dilute sulfuric acid gives a salt and hydrogen gas. (iron (ii) sulfate and hydrogen gas).
The equation for the reaction is;
Fe(s) + H2SO4 (aq) = FeSO4(aq) +H2(g)
Answer:
low weight and great area
Explanation:
The correct answer is A. A test tube of zinc oxide. Zinc oxide is a compound which is a pure substance composed of two or more elements. They can only be separated or broken down into its individual elements or smaller compounds by chemical means. Therefore, the answer is a test tube of zinc oxide.