1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nezavi [6.7K]
3 years ago
8

The filling of which orbital is represented by the transition metals in period 4? 3d 3s 2s 2p

Chemistry
2 answers:
Natali5045456 [20]3 years ago
8 0

Answer:

3d

Explanation:

Transition metal are elements having partially filled d sub shell. In these metals last electron is filled in d sub shell.

General electronic configuration of transition metal: (n-1)^{1-10}ns^{1-2}

Where, n = outermost shell.

Period 4 means, last shell no. is 4.

For transition metals of period 4,

General electronic configuration: 3d^{1-10}4s^{1-2}

for example, Fe belong to periods 4.

Electronic configuration of Fe: [Ar]3d^64s^2

So, filling of 3d orbital is represented by transition metal of 4.

pogonyaev3 years ago
3 0
Transition metals are the metal located in the center block of the periodic table. Also, this block represents the D sublevel.

So, the answer is 3d.

Also, keep in mind that the D block starts "one period late". this means that if you are in period 4, the 3d orbital starts. if you are in period 5, that where 4d starts.
You might be interested in
153 mL of 2.5 M HF is reacted with an excess of Ca(OH)2. How many grams of CaF2 will be produced?
Delvig [45]

Answer:

15 g

Explanation:

Data given:

amount of  HF  = 153 mL  2.5 M HF

amount of Ca(OH)₂ = Excess

grams of CaF₂ = ?

Reaction Given:

                2HF + Ca(OH)₂ ------→ 2H₂O + CaF₂

Solution:

First we have to find number of moles of HF in 153 mL of 2.5 M HF

For this we will use following formula

               Molarity = moles of solute / liter of solution

Rearrange above equation

               moles of solute =  Molarity x liter of solution . . . . . (1)

Put values in above equation (1)

               moles of solute =  2.5 x 1 L

              moles of solute =  2.5

So,

we come to know that there are 2.5 moles of solute (HF) in 1 L of solution

Now how many moles of solute will be present in 153 ml of solution

Convert 153 mL to Liter

1000 mL = 1 L

153 mL = 153/1000 = 0.153 L

Apply Unity Formula

                       2.5 moles HF ≅ 1 L solution

                        X moles of HF ≅ 0.153 L solution

              moles of HF = 2.5 moles x 0.153 mL solution / 1 L solution

              moles of HF =  0.383 moles

  • So, 153 mL contains 0.383 moles of HF

Now Look at the reaction:

                     2HF + Ca(OH)₂ ------→ 2H₂O + CaF₂

                    2 mol                                          1 mol

From the reaction we come to know that 2 moles of HF gives 1 mole of CaF₂ then how many moles of CaF₂  will be produced from o.383 moles of HF

Apply Unity Formula

                       2 moles HF ≅ 1 mole of CaF₂

                       0.383 moles of HF ≅ X moles of CaF₂

              moles of CaF₂  = 0.383 moles x 1 mole / 2 mol

              moles of CaF₂ =  0.192 moles

  • So, 0.192 moles of  CaF₂ will be produced by 0.383 moles of HF

Now we will find mass of 0.192 moles of  CaF₂

Formula will be used

          mass in grams = no. of moles x molar mass . . . . . . . (2)

molar mass of CaF₂ = 40 + 2(19)

molar mass of CaF₂ = 40 + 38 =  78 g/mol

Put values in eq. 2

        mass in grams = 0.192 x 78 g/mol

        mass in grams = 14.976 g

rounding the value

          mass in grams = 15 g

So,153 mL of 2.5 M HF is reacted with an excess of Ca(OH)₂ will produce 15 g of CaF₂.

6 0
4 years ago
How many protons electrons and neutrons does the following isotopes contain 1H+
Rus_ich [418]

Answer: 1 proton, 0 electron and 1 neutron are present in 1 H⁺ isotope.

8 0
3 years ago
What is the healthy percentage of body fat for men?
Jet001 [13]

Answer:

Ideal body fat percentage for men

Category Percentage

Essential fat     2-5%

Athletes             6-13%

Fitness             14-17%

Acceptable     18-24%

Explanation:

5 0
3 years ago
We want to find how much charge is on the electrons in a nickel coin. follow this method. a nickel coin has a mass of about 5 g.
Lady bird [3.3K]
The mass of a nickel coin is 5 g.
1 mol of Ni weighs 58 g. 1 mol contains 6.022 x 10²³ atoms of Ni.
therefore in 58 g  there are 6.022 x 10²³ atoms of Ni
then in 5 g the number of Ni atoms are - 6.022 x 10²³ /58 x 5 = 5.2 x 10²² Ni atoms
Therefore number of Ni atoms are 5.2 x 10²² atoms in a nickel coin

3 0
3 years ago
What are some examples of rapid changes
SSSSS [86.1K]
1) color change - for example, when bleach is shot down by mistake, in colored clothing;

2) gas release - for example, when playing an effervescent tablet in water.

3) heat release - for example in combustion;

hope this helps!.
7 0
3 years ago
Other questions:
  • Help! 15 Points!<br><br> Science!
    10·2 answers
  • Based upon the mass of baking soda (NaHCO3) and using an excess of HCl in this experiment, you will 1) determine the mass of CO2
    7·2 answers
  • In an operating voltaic cell, reduction occurs
    14·2 answers
  • Formula for aluminum and bromine
    5·1 answer
  • You have 250mL of 3M HCI. What volume will you have if you dilute it to 0.5M?
    6·1 answer
  • Identify the MOs that react to form cyclohexene. HOMO of 1,3-butadiene and LUMO of ethylene LUMO of 1,3-butadiene and LUMO of et
    6·1 answer
  • What are the 5 functions of the skelatal system
    6·1 answer
  • How many moles of water will be produced when 8 moles of ethane are burned?
    9·1 answer
  • Using the diagram below, which rock layer is older than the Chinle Formation?
    12·1 answer
  • For which elements are outer electrons and valence electrons the same?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!