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Nezavi [6.7K]
3 years ago
8

The filling of which orbital is represented by the transition metals in period 4? 3d 3s 2s 2p

Chemistry
2 answers:
Natali5045456 [20]3 years ago
8 0

Answer:

3d

Explanation:

Transition metal are elements having partially filled d sub shell. In these metals last electron is filled in d sub shell.

General electronic configuration of transition metal: (n-1)^{1-10}ns^{1-2}

Where, n = outermost shell.

Period 4 means, last shell no. is 4.

For transition metals of period 4,

General electronic configuration: 3d^{1-10}4s^{1-2}

for example, Fe belong to periods 4.

Electronic configuration of Fe: [Ar]3d^64s^2

So, filling of 3d orbital is represented by transition metal of 4.

pogonyaev3 years ago
3 0
Transition metals are the metal located in the center block of the periodic table. Also, this block represents the D sublevel.

So, the answer is 3d.

Also, keep in mind that the D block starts "one period late". this means that if you are in period 4, the 3d orbital starts. if you are in period 5, that where 4d starts.
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Explanation:

Given data:

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Partial pressure of argon = 50.0 KPa

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Solution:

Total pressure = P(N₂) + P(O₂) + P(Ar)

98.5 KPa = 22.0 KPa +P(O₂) + 50.0 KPa

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Percentage abundance of 123 Sb is = 42.8 %

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For second isotope, 123 Sb:

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Thus,  

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120.9038x+122.9042\left(100-x\right)=12176.01

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