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Cloud [144]
2 years ago
14

SPEED THAT INCLUDES THE DIRECTION is ____

Physics
1 answer:
marin [14]2 years ago
7 0

Answer:

Velocity

Explanation:

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If a moving object travels for a distance of 160 m. In 20 seconds what’s the average speed
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Answer:

8.00

Explanation:

you have to divide

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3 years ago
PLZZ HELP ME ASAP!! If you get it correct I will give brainliest and 50 POINTS!!
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6 0
3 years ago
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ASK YOUR TEACHER Red blood cells often can be charged. Two red blood cells are separated by 1.11 m and have an attractive electr
makvit [3.9K]

Answer:

q2 = -1.61*10^-5 C.

Explanation:

It was given that,

F = 0.985N

q1 = +8.40 X10-6 C

q2 = ?

r = 1.11 m

k = 9 x 10^9 (standard)

It generally follows that, if force is attractive, charge will be negative.

force, F = kq1q2/r^2

0.985 = 9*10^9*8.40*10^-6*q2/1.11^2

75600q2 = 0.985*1.11^2

75600q2 = 1.2136

q2 = 1.2136/75600 = 1.60529

q2 = -1.61*10^-5 C.

7 0
3 years ago
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A spring with a force constant of 5.2 N/m has a relaxed length of 2.45 m. When a mass is attached to the end of the spring and a
Elodia [21]

Answer:

Elastic potential energy, E = 3.26 J

Explanation:

It is given that,

Force constant of the spring, k = 5.2 N/m

Relaxed length of the spring, X = 2.45 m

When the mass is attached to the end of the spring, the vertical length of the spring is, x' = 3.57 m

To find,

The elastic potential energy stored in the spring.

Solution,

The extension in the length of the spring is given by :

x=x'-X

x=3.57\ m-2.45\ m

x = 1.12 m

The elastic potential energy of the spring is given by :

E=\dfrac{1}{2}kx^2

E=\dfrac{1}{2}\times 5.2\times (1.12)^2

E = 3.26 J

So, the elastic potential energy stored in the spring is 3.26 joules.

6 0
3 years ago
If the initial upward speed of the ball in Activity 7 C.2 is 10m/s, and the ball is releasedat a height of 1.5 m above the oor,
Ulleksa [173]

Answer:

6.5 m above the floor and 5 m above Christine's hand when it reaches the maximum height.

Explanation:

Let g = 10 m/s2 be the gravitational deceleration that affects the ball vertical motion so it comes to the maximum height at 0 speed. We can use the following equation of motion to find out the distance traveled by the ball from where it's thrown:

v^2 - v_0^2 = 2g\Delta s

where v = 0 m/s is the final velocity of the ball when it reaches maximum level, v_0 = 10m/s is the initial velocity of the ball when it starts, g = -10 m/s2 is the deceleration, and \Delta s is the distance traveled, which we care looking for:

0^2 - 10^2 = -2*(-10)\Delta s

\Delta s = 100 / (2 * 10) = 5 m

So the ball is 5 m above Christine' hands when it reaches maximum height, and since the hand is 1.5 m above the floor, the ball is 5 + 1.5 = 6.5 m above the floor when it reaches maximum height.

5 0
3 years ago
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