Answer:
Elastic potential energy, E = 3.26 J
Explanation:
It is given that,
Force constant of the spring, k = 5.2 N/m
Relaxed length of the spring, X = 2.45 m
When the mass is attached to the end of the spring, the vertical length of the spring is, x' = 3.57 m
To find,
The elastic potential energy stored in the spring.
Solution,
The extension in the length of the spring is given by :
x = 1.12 m
The elastic potential energy of the spring is given by :
E = 3.26 J
So, the elastic potential energy stored in the spring is 3.26 joules.