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3 years ago

6

Given the following constants for a standard form quadratic equation, determine the nature of its roots. Please wait for photo t

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1 answer:

lisabon 2012 [21]3 years ago

3 0

$ax^2+bx+c=0$
$3x^2+3x+2=0$
$D=b^2-4ac=3^2-4*3*2=9-24=-15$
$D$ , so there are no real solutions.

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Kerri said that the product of 3.93 and 0.07 would be about 4 and would have two decimal places. Is she correct?

oee [108]

Answer:

No.

Step-by-step explanation:

This type of problem is actually a trick problem. The question indicates that the PRODUCT of 3.93 and 0.07 would be about 4. The question is referring to the answer of the two values Multiplied to each other.

To visualize the question, we have:

3.93 x 0.07

This would give us:

0.2751

Kerri would be correct if she was looking for the SUM of the two values.

This would be:

3.93 + 0.07

This would give us:

4

Therefore in trick problems like this ones, it is better to look at what exactly is being asked.

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4 years ago

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I NEED HELP special right triangle 45-45-90

poizon [28]

Answer:

x=6

y=9

Step-by-step explanation:

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3 years ago

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Carpeting costs 9.99 a yard. If jan buys 17.4 yards, how much will it cost her (round your anwser to the nearest hundreth

aalyn [17]

To get the answer, multiply 9.99 x 17.4 yards. That will give you the answer 173.826. That rounds to 173.83

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%28x-4%29%5E%7B2%7D%20%5E%2B%28y-3%29%5E%7B2%7D%20%3D16" id="TexFormula1" title="(x-4)^{2} ^+(

sergij07 [2.7K]

an equation for a circle has formula

(x-m)² + (y-n)² = r²

where (m,n) is its center

and r is its radius

so, the equation has center (4,3) and radius 4

the equation is derived from the pythagorean theorem

8 0

3 years ago

Find equation of set of points pieces that its distance from the point 3, 4, -5 and -2, 1, 4 are equal.

Gnesinka [82]

Answer:

Step-by-step explanation:

Suppose we a point $P(x,y,z)$ such that its distance from either the point $A(3,4,-5)$ or $B(-2,1,4)$ is the same.

Using this information we can formula:

distance AP = distance BP

first, let's find the distance from AP, using the distance formula.

$r = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}$

$AP = \sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2}$

similarly, we can find the distance BP

$BP = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

since both distances are exactly the same we can equate them

$AP = BP$

$\sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2} = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

we can simplify it a bit squaring both sides, and getting rid of the subscripts.

$(3 - x)^2 + (4 - y)^2 + (-5 - z)^2 = (-2 - x)^2 + (1 - y)^2 + (4 - z)^2$

what we have done here is formulated an equation which consists of any point P that will have the same distance from (3,4,-5) and (-2,1,4).

To put it more concretely,

This is the equation of the the plane from that consists of all points (P) from which the distance from both (3,4,-5) and (-2,1,4) are equal.

3 0

3 years ago