1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svetoff [14.1K]
2 years ago
5

Choose all the answers that apply.

Chemistry
2 answers:
ziro4ka [17]2 years ago
7 0

Answer:

1, 5, 3

Explanation:

Nana76 [90]2 years ago
6 0

<u>Answer:</u>

<em>1, 3, and 5</em>

<u>Further Information:</u>

Careless farming - <em>increases erosion</em>

Crop rotation - <em>does not increase erosion</em>

Leaving fields unplanted- <em>increases erosion</em>

Clearing forests - <em>does not increase erosion</em>

Contour plowing - <em>increases erosion</em>

Hope this helps and brainliest would be greatly appreciated!!

You might be interested in
It takes Serina 0.25 hours to drive to school. Her route is 16 meters long. What is
Yakvenalex [24]

Answer:

60 (1 hour) × 0.25 = 15 minutes

15 ÷ 16 = 0.9375 meters per minute

5 0
3 years ago
For the following reactions, predict the products and write the balanced formula equation, complete ionic equation, and net ioni
stealth61 [152]

Answer:

.

Explanation:

To predict the products of these reactions we need to know the kind of reactions. All these reactions are double replacement reaction. In these kinds of reactions, the products will be the result of exchanging ions in the reactants. So, the first step is to identify the ions.  

For the reaction, we have Hg2(NO3)2 and CuSO4.  We have the ions Hg+1,  NO3-1,   Cu+2 and SO4-2  

The way to make this exchange is putting together positive in one species with the negative of the other species. Following that rule we have

Hg^{+1}  - - -  (SO_{4})^{-2}[/text]&#10;the oxidation number will tell you the subscript for each species in the compound. In this case, is Hg2(SO4)  [tex]Cu^{+2} - - -  (NO_{3})^{-1}  - - ->  Cu(NO_{3})_{2} [/text]  &#10;So, the products for this reaction will be&#10;  [tex]Hg_{2} (NO_{3})_{2}(aq) + CuSO_{4}(aq)  -->  Hg_{2}SO_{4} + Cu(NO_{3})_{2}[/text]&#10;&#10;After this, we proceed to balance the equation. For this, we check that we have the same number of each element on both sides of the equation. In this case, we can see that we have the same number, so the equation is balanced.  Finally, we check the rules of solubility to see if the species are soluble in water or not. In this case sulfates area always soluble except for mercury so Hg2(SO4) precipitates in the solution (pre). Nitrates are always soluble so Cu(NO3)2 is soluble (aq)  &#10;[tex] Hg_{2}(NO_{3})_{2}(aq) + CuSO_{4}(aq)  - -> Hg_{2}SO_{4} (pre) + Cu(NO_{3})_{2}(aq)

The complete ionic equation allows to show which of the reactants or products exist primarily as ions.  For this reaction this will be:

2Hg^{+1}(aq)  + 2(NO_{3})^{-1}(aq) + (SO_{4})^{-2}(aq)  + Cu^{+2}(aq)    -->  Hg_{2}SO_{4} (pre)+ Cu^{+2}(aq)    + (NO_{3})^{-1}(aq) [/text]&#10;&#10;To get net ionic equation we take away the ions that did not participate in the reactions. In other words the ones that are the same on both sides in the equation. In this case we see that [tex] Cu^{+2}(aq)   and  (NO_{3})^{-1}(aq) [/text] are the same on both sides so those ions are not include in the net ionic equation.  This is:&#10;[tex] 2Hg^{+1}(aq)  + (SO_{4})^{-2}(aq)  -->  Hg_{2}SO_{4} (pre) [/text]&#10;&#10;B [tex] Ni(NO_{3})_{2}(aq) + CaCl_{2}(aq)

ions (1) Ni^{+2}  and (NO_{3})^{-1}

ions (2) Ca^{+2} and Cl^{-1}

Exchanging  

Ni^{+2}  ---- Cl^{-1}  -->  NiCl_{2}  

Ca^{+2} ---  (NO_{3})^{-1}  -->  Ca(NO_{3})_{2}  

Products  

Ni(NO_{3})_{2}(aq) + CaCl_{2}(aq) -->  NiCl_{2}  + Ca(NO_{3})_{2}  

The equation is already balanced

Chlorides are always soluble except Ag+, TI+, Pb+2 and Hg2+2. NiCl2 is soluble (aq)

Nitrates are always soluble. Ca(NO3)2 is soluble (aq)  

Since both compounds are soluble, we can say that there is not reaction.

Complete ionic equation  

Ni^{+2}(aq) + 2(NO_{3})^{-1}  (aq) + Ca^{+2}(aq) + 2Cl^{-1}(aq) - - > Ni^{+2}(aq) + 2(NO_{3})^{-1}  (aq) + Ca^{+2}(aq) + 2Cl^{-1}(aq)

Net ionic equation:

The ions in both sides of the equation are the same so all of them are cancelled and we cannot get a net ionic equation this explains why there is no reaction in this case.  

C K_{2}CO_{3}(aq) + MgI_{2}(aq)

Ions(1) K^{+1}  and (CO_{3})^{-2}

Ions(2) Mg^{+2}  and l^{-1}

Exchanging  

K^{+1}  ---  l^{-1}  - - >  KI

Mg^{+2}  ---  (CO_{3})^{-2}  - - >  Ca(CO_{3})

Products  

K_{2}CO_{3}(aq) + MgI_{2}(aq) - ->   Kl + MgCO_{3}  

The equation is not balanced

Balance equation is  

K_{2}CO_{3}(aq) + MgI_{2}(aq) - ->  2Kl (aq) + MgCO_{3} (pre)  

iodides are always soluble except Ag+, TI+, Pb+2 and Hg2+2. KI is soluble (aq)

carbonates are always insoluble except group 1 cations. MgCO3 is insoluble (pre)

complete ionic equation  

2K^{+1}(aq)  + (CO_{3})^{-2}(aq)  + Mg^{+2}(aq)   + 2l^{-1}(aq)  - - > MgCO_{3} (pre) + 2K^{+1}(aq)  + 2l^{-1}(aq)  

Net ionic equation

(CO_{3})^{-2}(aq)  + Mg^{+2}(aq)  - - > MgCO_{3} (pre)  

D Na_{2}CrO_{4}(aq) + AlBr_{3}(aq)  

Ions(1) Na^{+1}  and (CrO_{4})^{-2}

Ions(2) Al^{+3} and Br^{-1}

Exchanging  

Na^{+1}  ---- Br^{-1} - ->  NaBr  

Al^{+3} ---  (CrO_{4})^{-2} - ->  Al_{2}(CrO_{4})_{3}

Products  

Na_{2}CrO_{4}(aq) + AlBr_{3}(aq) - ->  NaBr  + Al_{2}(CrO_{4})_{3}

The equation is not balanced

Balance equation is  

3Na_{2}CrO_{4}(aq) + 2AlBr_{3}(aq) - -> 6NaBr  + Al_{2}(CrO_{4})_{3}

bromides are always soluble except Ag+, TI+, Pb+2 and Hg2+2. NaBr is soluble (aq)

chromates are always insoluble except group 1 cations. Al2(CrO4)3 is insoluble  (pre)

3Na_{2}CrO_{4}(aq) + 2AlBr_{3}(aq) - ->  6NaBr(aq) + Al_{2}(CrO_{4})_{3}(pre)

Complete ionic equation

6Na^{+1}(aq)  + 3(CrO_{4})^{-2}(aq) + 2Al^{+3}(aq) + 6Br^{-1}(aq) - -> Al_{2}(CrO_{4})_{3}(pre) +6Br^{-1}(aq) +  6Na^{+1}(aq)  

Net ionic equation

3(CrO_{4})^{-2}(aq) + 2Al^{+3}(aq) - -> Al_{2}(CrO_{4})_{3}(pre)  

6 0
3 years ago
The picture is above^ someone help me please :)
Ronch [10]

Answer:

idk plz do not report

Explanation:

8 0
3 years ago
Calculate the grams of C6H6 needed to produce 25 g of CO2<br> Show your work
Anna007 [38]

Answer:

The given reaction is a combustion reaction of benzene,

C

6

H

6

. From its balanced chemical equation,

2

C

6

H

6

+

15

O

2

→

12

C

O

2

+

6

H

2

O

,

the mass of carbon dioxide

(

C

O

2

)

produced from 20 grams (g) of

C

6

H

6

is determined through the molar mass of the two compounds, given by,

M

M

C

O

2

=

44.01

g

/

m

o

l

M

M

C

6

H

6

=

78.11

g

/

m

o

l

and their mole ratio:

12

m

o

l

C

O

2

2

m

o

l

C

6

H

6

→

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

With this,

m

a

s

s

o

f

C

O

2

=

(

20

g

C

6

H

6

)

(

1

m

o

l

C

6

H

6

78.11

g

C

6

H

6

)

(

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

)

(

44.01

g

C

O

2

1

m

o

l

C

O

2

)

=

(

20

)

(

6

)

(

44.01

)

g

C

O

2

78.11

=

5281.2

g

C

O

2

78.11

m

a

s

s

o

f

C

O

2

=

67.6

g

C

O

2

Therefore, the mass in grams of

C

O

2

formed from 20 grams of

C

6

H

6

is

67.6

g

C

O

2

.

it is a problem of app

3 0
2 years ago
Which of the following elements is likely to show additional stability in its electronic configurations because of filled and ha
kodGreya [7K]
Ah is gold and Rh is rhodium and Os is osmium and Ir iridium
3 0
2 years ago
Other questions:
  • A 250-ml sample of na2so4 is reacted with an excess of bacl2. if 5.28 g baso4 is precipitated, what is the molarity of the na2so
    7·1 answer
  • 19 which term represents an intermolecular force in a sample of water
    15·1 answer
  • What is the mass number for aluminum?
    7·1 answer
  • The distance from one place to another
    10·2 answers
  • Suppose that you have 115 mL of a buffer that is 0.460 M in both benzoic acid ( C 6 H 5 COOH ) and its conjugate base ( C 6 H 5
    5·1 answer
  • Dissolved minerals trapped in magma under tremendous pressure provide the force for a volcanic eruption.
    14·2 answers
  • What causes your vocal cords to vibrate a)mucas b)air c)chemicals
    6·1 answer
  • To have a system you need more than one magnet .<br> true or false
    14·2 answers
  • SOMEONE HELP ME ANSWER FOSSIL RECORD PLS I DONT KNOW THE ANSWER I NEED TO KNOW ASAP
    14·1 answer
  • How are water and minerals transported and used in vascular plants?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!