Please answer and thanks

Unpolarized light with intensity I0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal polariz

nordsb [41]

Answer:

$0.276I_0$

Explanation:

When unpolarized light passes through a polarizer, only the component of the light vibrating in the direction parallel to the axis of the polarizer passes through: therefore, the intensity of light is reduced by half, since only 1 out of 2 components passes through.

So, after the first polarizer, the intensity of light passing through is:

$I_1=\frac{I_0}{2}$

Where $I_0$ is the initial intensity of the unpolarized light.

Then, the light (which is now polarized) passes through the second polarizer. Here, the intensity of the light passing through the second polarizer is given by Malus Law:

$I_2=I_1 cos^2 \theta$

where:

$\theta$ is the angle between the axes of the two polarizers

In this problem the angle is

$\theta=42^{\circ}$

So the intensity after of light the 2nd polarizer is:

$I_2=I_1 (cos 42^{\circ})^2=\frac{I_0}{2}(cos 42^{\circ})^2=0.276I_0$

8 0

3 years ago

[W]?

natali 33 [55]

87 km I think .........

5 0

2 years ago

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

natima [27]

The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.

<h3>Hooke's Law</h3>

Hooke's law states that the force applied to an elastic material is directly proportional to its extension, provided its elastic limit is not exceeded.

To calculate the amount of work done by Hooke's law, first, we need to find the force constant of the spring.

Formula:

F = ke................. Equation 1

Where:

F = Force applied
k = Spring constant
e = extension

make k the subject of the equation

k = F/e................ Equation 2

From the question,

Given:

F = 450 N
e = 30 cm = 0.3 m

Substitute these values into equation 2

k = 450/0.3
k = 1500 N/m.

Finally, To find the work done in stretching the spring from 50 cm to 80 cm, we use the formula below.

W = ke²/2........... Equation 3

Where:

W = Work done
k = spring constant
e = extension

Also, From the question,

Given:

e = (80-50) = 30 cm = 0.3 m
k = 1500 N/m

Substitute these values into equation 3

W = 1500(0.3²)/2
W = 67.5 J.

Hence, The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.

Learn more about Hooke's law here: brainly.com/question/12253978

5 0

2 years ago

Why can't birds fly in space

blagie [28]

Answer:

wouldn't they be dead and there's no oxygen in space....right???

4 0

2 years ago

Read 2 more answers

If the period of oscillation of a simple pendulum is 4s, find its length. If the velocity of the bob

Natalija [7]

Answer:

Explanation:

Because we assume the pendulum is a "mathematical pendulum" (neglecting the moment of inertia of the bob), we can find:

$T=2\pi\sqrt{\frac{L}{g}} \rightarrow 4=2\pi\sqrt{\frac{L}{9.81}} \rightarrow \frac{4}{\pi^{2}}=\frac{L}{9.81} \rightarrow L \approx 3.97 m$

By using the $y=A\sin(\omega t) \rightarrow v = \frac{dy}{dt}=\omega A \cos\omega t = \omega\sqrt{A^{2}-y^{2}}$

The mean position is the position when <em>y</em> = 0, so:

$\omega = \frac{2\pi}{T}=\frac{2\pi}{4}=0.5\pi$ rad/s

and $v = \omega A \rightarrow A=\frac{40}{0.5\pi}=\frac{80}{\pi}$ in centimeters (cm).

4 0

2 years ago