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kondaur [170]
3 years ago
5

How far can a bus carrying small children, travel at a rate of 60 km per hour travel in 2 1/2 hours?

Physics
1 answer:
Rudiy273 years ago
5 0

<h2>150km</h2>

Explanation:

<h3><em><u>speed</u></em><em> </em><em>=</em><em> </em><em>6</em><em>0</em><em>k</em><em>m</em><em>/</em><em>h</em><em>r</em><em>.</em></h3><h3><u><em>t</em><em>i</em><em>m</em><em>e</em></u><em> </em><em>=</em><em> </em><em>2</em><em>¹</em><em>/</em><em>2</em><em> </em><em>h</em><em>r</em><em> </em></h3><h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>5</em><em>/</em><em>2</em><em> </em><em>h</em><em>r</em></h3><h3><u><em>d</em><em>i</em><em>s</em><em>t</em><em>a</em><em>n</em><em>c</em><em>e</em></u><em> </em><em>=</em><em> </em><em>s</em><em>p</em><em>e</em><em>e</em><em>d</em><em> </em><em>×</em><em> </em><em>t</em><em>i</em><em>m</em><em>e</em></h3><h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>6</em><em>0</em><em> </em><em>×</em><em>5</em><em>/</em><em>2</em></h3><h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>5</em><em>0</em><em>k</em><em>m</em></h3>

<h2><em>M</em><em>A</em><em>R</em><em>K</em> ME AS BRAINLIST</h2>
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On what does kinetic energy depend?
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Gantt charts are A. widely used network techniques. B. not widely used. C. planning charts used to schedule resources and alloca
kotykmax [81]

Answer:

planning charts used to schedule resources and allocate time is the correct answer

Explanation:

  • Gantt Charts are a project planning tool used to track the projects from the start to endpoint.
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3 years ago
A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of th
zheka24 [161]

The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m  = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Learn more on momentum here: brainly.com/question/402617

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2 years ago
What is the net power needed to change the speed of a 1600-kg sport utility vehicle from 15.0 m/s to 40.0 m/s in 4.00 seconds
Sergio039 [100]

Answer:

The net power needed to change the speed of the vehicle is 275,000 W

Explanation:

Given;

mass of the sport vehicle, m = 1600 kg

initial velocity of the vehicle, u = 15 m/s

final velocity of the vehicle, v = 40 m/s

time of motion, t = 4 s

The force needed to change the speed of the sport vehicle;

F = \frac{m(v-u)}{t} \\\\F = \frac{1600(40-15)}{4} \\\\F = 10,000 \ N

The net power needed to change the speed of the vehicle is calculated as;

P_{net} = \frac{1}{2} F[u + v]\\\\P_{net} = \frac{1}{2} \times 10,000[15 + 40]\\\\P_{net} = 275,000 \ W

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