The question is asking to calculate the object's speed v1, v2, v3 at the certain time is the given of the problem, in my calculation, I would say that the speed would be 2m/s, 1.5m/s, 0.22m/s. I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarification
' +4 m/s² ' means that the pigeon's speed is 4 m/s greater every second.
Starting from zero speed, after 10 seconds, its speed is
(10 x 4m/s) = 40 m/s.
We can't say anything about its velocity, because we have
no information regarding the direction of its flight.
Answer:
<em>The bullet was 0.52 seconds in the air.</em>
Explanation:
<u>Horizontal Motion
</u>
It occurs when an object is thrown horizontally with a speed v from a height h.
The object describes a curved path ruled exclusively by gravity until it hits the ground.
To calculate the time the object takes to hit the ground, we use the following equation:

Note it doesn't depend on the initial velocity but on the height.
The bullet is fired horizontally at h=1.3 m, thus:


t = 0.52 s
The bullet was 0.52 seconds in the air.
Elevation would be showing you what height you are at, energy would be like what force your putting into the object.