C = 3 uf = 3 × 10^(-6) f
v = 6volts
Q = C.v
= <span>3 × 10^(-6) </span>× 6
= 18 × 10^(-6)
= 1.8 = 10^(-5)
Without friction, the amount of work only depends on the final height,
and is not affected by the route used to get there.
If the ramp has no friction, then it has no effect on the total amount
of work done. The work to lift the load straight up is the same.
If the ramp has some friction, then it takes more work to use the ramp
than to lift the load straight up. Then the work to lift the load straight up
would be less than when the ramp is used.
Answer: 2.74
Explanation:
We can solve this problem using the stopping distance formula:
Where:
is the distance traveled by the car before it stops
is the car's initial velocity
is the coefficient of friction between the road and the tires
is the acceleration due gravity
Isolating :
Solving:
This is the coefficient of friction
Answer:
<h2>0.094 kg</h2>
Explanation:
Latent heat of vaporization of 
at 37°C is 
.
When the sweat on our body evaporates, it absorbs energy from our body to overcome it's Latent heat of vaporisation. Thus our body cools down when sweat evaporates.
So, Energy absorbed by sweat to evaporate = Energy lost by body
Specific heat capacity of human body = 
. Jogger weights 60.4 kg. Body temperature decreases by 
Energy absorbed from body = 
∴ 0.094 kg of sweat has evaporated from the body.
Answer:
Same weight so neither is heavier
