Answer:
h = 61.16[cm]
Explanation:
In order to solve this problem we must use the principle of energy conservation. Which tells us that energy is conserved or equal in two points in space for an instant in time.
In this way we will have the points A & B, the point A for the moment before shooting and the moment B when the Dart is in the highest position.
In this way the energy is:
Now we must identify the energies in the moments A & B. in the instant A we have the spring compressed, in such a way that only elastic energy is stored.
where:
k = spring constant = 20 [N/m]
x = distance = 0.3 [m]
Now, at the moment when the dart is in the highest position (B), it means that it does not go up anymore, that is, its movement is zero, and therefore its kinetic energy is zero, in this way the energy at the highest point corresponds to potential energy.
where:
m = mass = 0.15[kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation [m]
Now replacing:
![\frac{1}{2} *20*(0.3)^{2}=0.15*9.81*h\\0.9=1.4715*h\\h=0.61[m]\\or\\h = 61.16[cm]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A20%2A%280.3%29%5E%7B2%7D%3D0.15%2A9.81%2Ah%5C%5C0.9%3D1.4715%2Ah%5C%5Ch%3D0.61%5Bm%5D%5C%5Cor%5C%5Ch%20%3D%2061.16%5Bcm%5D)
Answer: 
Explanation:
Given
Car starts from the state of rest and acquires a velocity of 
in 6 minutes
Final velocity in m/s is 
Using equation of motion
Distance covered in 360 s
Answer:
Generally, the lowest overtone for a pipe open at one end and closed would be at y / 4 where y represents lambda, the wavelength.
Since F (frequency) = c / y Speed/wavelength
F2 / F1 = y1 / y2 because c is the same in both cases
F2 = y1/y2 * F1
F2 = 3 F1 = 750 /sec
Note that L = y1 / 4 = 3 y2 / 4 for these wavelengths to fit in the pipe
and y1 = 3 y2
Explanation:
Let east direction is negative and west direction is positive. The acceleration of an object is given by :
Where
v is the final speed
u is the initial speed
t is the time taken
As the car decelerates, the final speed of the car is less as compared to the initial speed. As a result, its acceleration is negative. It means the car travels eastward and slows down. Hence, this is the required solution.
Answer:
(A) 1.43secs
(B) -2.50m/s^2
Explanation:
A commuter backs her car out of her garage with an acceleration of 1.40m/s^2
(A) When the speed is 2.00m/s then, the time can be calculated as follows
t= Vf-Vo/a
The values given are a= 1.40m/s^2 , Vf= 2.00m/s, Vo= 0
= 2.00-0/1.40
= 2.00/1.40
= 1.43secs
(B) The deceleration when the time is 0.800secs can be calculated as follows
a= Vf-Vo/t
= 0-2.00/0.800
= -2.00/0.800
= -2.50m/s^2
