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3 years ago

URGENT PLEASE ANSWER

Physics

1 answer:

Anettt [7]3 years ago

6 0

Answer:

3.523 * 10²² N

Explanation:

Newton's Law of Universal Gravitation:

$\displaystyle \bf{F=G\frac{m_1 m_2}{r^2}$
F = force of gravity between two objects
G = gravitational constant (6.67 * 10⁻¹¹ Nm²kg⁻²)
m₁ = mass of object #1
m₂ = mass of object #2
r = distance between the center of mass of two objects

We are given the mass of the sun (m₁) and its distance from Earth (r). We want to find the value of F.

The mass of Earth (m₂) is 5.972 * 10²⁴ kg and we know the gravitational constant (G).

Let's plug these known values into the equation to solve for F.

$\displaystyle \bf{F=6.67\cdot10^-^1^1 \Big [ \frac{(1.99\cdot 10^3^0)(5.972\cdot 10^2^4)}{(150\cdot 10^9)^2} \Big ]$

Plugging this into your calculator will output a value of

$\displaystyle \bf{ F = 3.523028782\cdot 10^2^2$

The gravitational force between the sun and the Earth is approximately:

$\displaystyle \bf{F=3.523\cdot 10^2^2 \ N$

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Answer:

the quarterback will be moving back at speed of 0.080625 m/s

the distance moved horizontally by the quarterback is 0.0241875 m or 2.41875 cm

Explanation:

Given the data in the question;

How fast will he be moving backward just after releasing the ball?

using conservation of momentum;

m₁v₁ = m₂v₂

v₂ = m₁v₁ / m₂

where m₁ is initial mass ( 0.43 kg )

m₂ is the final mass ( 80 kg )

v₁ is the initial velocity ( 15 m/s )

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so we substitute

v₂ = ( 0.43 × 15 ) / 80

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v₂ = 0.080625 m/s

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b) Suppose that the quarterback takes 0.30 to return to the ground after throwing the ball. How far d will he move horizontally, assuming his speed is constant?

we make use of the relation between time, distance and speed;

s = d/t

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t is time ( 0.30 s )

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d = 0.080625 × 0.30

d = 0.0241875 m or 2.41875 cm

Therefore, the distance moved horizontally by the quarterback is 0.0241875 m or 2.41875 cm

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The magnetic field at the centre of a toroid is 2.2-mT. If the toroid carries a current of 9.6 A and has 6.000 turns, what is th

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Answer:

Radius, r = 0.00523 meters

Explanation:

It is given that,

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We need to find the radius of the toroid. The magnetic field at the center of the toroid is given by :

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$r=\dfrac{\mu_oNI}{2\pi B}$

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r = 0.00523 m

$r=5.23\times 10^{-3}\ m$

So, the radius of the toroid is 0.00523 meters. Hence, this is the required solution.

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Answer:

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