Question

A car is initially moving at 10.5 m/s and accelerates uniformly to reach a speed of 21.7 m/s in 4.34 s. How far did the car move during this acceleration?
A. 69.9m
B. 6.99m
C. 69.6m/s
D. 6.99m/s

Answer 1

Answer:

A. 69.9m

Explanation:

Given parameters:

Initial velocity = 10.5m/s

Final velocity  = 21.7m/s

Time  = 4.34s

Unknown:

Distance traveled = ?

Solution:

Let us first find the acceleration of the car;

  Acceleration  = $\frac{v - u}{t}$

  v is final velocity

   u is initial velocity

   t is the time

     Acceleration  = $\frac{21.7 - 10.5}{4.34}$   = 2.58m/s²

Distance traveled;

     V² = U² + 2aS

    21.7² = 10.5² + 2 x 2.58 x S

   360.64 = 2 x 2.58 x S

     S = 69.9m