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Anettt [7]
3 years ago
11

What is that can fix pipe leak

Engineering
1 answer:
Serhud [2]3 years ago
5 0

Answer: For tiny leaks in pipes, use a compound stick available at most hardware stores. Simply rub the stick over the hole to stop the leak. The compound stick can even stop small leaks while the water is still running in the pipe. Epoxy paste can be applied only to dry pipes, and the water must be turned off. repair clamps An epoxy putty can be applied over the source of the leak to temporarily seal it. Immediately turn off the water supply upstream of the leaking pipes. Drain the water from the damaged line and ensure that the area to be patched is clean and dry so that the epoxy will properly adhere to the pipe.

Explanation:

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A plane surface 25 cm wide has its temperature maintained at 80°C. Atmospheric air at 25°C ows parallel to the surface
Gre4nikov [31]

Answer:

See the detailed answer in attached file.

Explanation :

Download docx
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3 years ago
What is integrated circuit package ​
enyata [817]

Answer:

Explanation:

, integrated circuit packaging is the final stage of semiconductor device fabrication, in which the block of semiconductor material is encapsulated in a supporting case that prevents physical damage and corrosion.

4 0
3 years ago
Read 2 more answers
Technician a s ays a shorted circuit can generate excessive heat. technician b says a shorted circuit will cause the circuit pro
Lerok [7]

Based on the information provided, the technician who is correct is: C. Both Technician A and Technician B.

<h3>What is an open circuit?</h3>

An open circuit can be defined as a type of electric circuit in which the continuity between the conducting wire (paths) has been broken or cut.

This ultimately implies that, an open circuit is designed and developed to prevent the flow of electric charges (electrons or currents) from one point in an electric circuit to another.

In Electrical engineering, a short usually causes an electric circuit protection device such as a fuse, circuit breaker, etc., to open when higher than normal current flows through the electrical circuit.

Read more on short circuit here: brainly.com/question/25018411

#SPJ1

Complete Question:

Technician A says a shorted circuit can generate excessive heat. Technician B says a shorted circuit will cause the circuit protection device to open. who is correct?

A. Technician A only

B. Technician B only

C. Both Technician A and B

D. Neither Technician A nor B

5 0
1 year ago
transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of
hram777 [196]
<h2>Corrected Question:</h2>

A step-up transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of 4100 V with a 16-mA current, what input current and voltage are needed?

<h2>Answer:</h2>

The input current and voltage needed are 443 mA and 148 V respectively.

<h2>Explanation:</h2>

In a step-up transformer, the relationship between the number of turns in its primary coil (N_{p}), the number of turns in its secondary coil (N_{s}), the input voltage (V_{p}), the output voltage (V_{s}), the input current (I_{p}), and the output current (I_{s}) is given by;

\frac{N_{s} }{N_{p} } = \frac{V_{s} }{V_{p} } = \frac{I_{p} }{I_{s} }

This implies that;

\frac{N_{s} }{N_{p} } = \frac{V_{s} }{V_{p} }  ---------------------(i)

\frac{N_{s} }{N_{p} } = \frac{I_{p} }{I_{s} }  ---------------------(ii)

From the question;

N_{p} = 26 turns

N_{s} = 720 turns

V_{s} = 4100V

I_{s} = 16mA = 16 x 10⁻³A

(a) Substitute these values into equation (ii) as follows;

\frac{720}{26} = \frac{I_{p} }{16*10^{-3}}

Solve for I_{p};

I_{p} = 720 x 16 x 10⁻³ / 26

I_{p} = 443 x 10⁻³

I_{p} = 443 mA

Therefore the input current needed is 443mA

(b) Also, substitute those values into equation (i) as follows;

\frac{720}{26} = \frac{4100 }{V_{p} }

Solve for V_{p};

V_{p} = 4100 x 26 / 720

V_{p} = 148 V

Therefore, the input current needed is 148 V

5 0
3 years ago
Two advantages of deforming steel at room temperature rather than at elevated temperatures are: (select 2 answers from the optio
Aleks [24]

Answer:

A AND C

Explanation:

Two advantages of deforming steel at room temperature rather than at elevated temperatures are: (select 2 answers from the options below)

A. better dimensional accuracy to allow form complex parts with complex geometries.

C. a smoother surface finish to allow elimination of finish machining and grinding operations.

7 0
3 years ago
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