What is the tool used to take off a wheel nut

At audio frequencies (below 20kHz), electromagnetic waves have very ____ wavelengths. The wavelength is typically much larger th

netineya [11]

Answer:

broad, transmission or power lines, electrical circuit theory

Explanation:

Electromagnetic waves have quite broad wavelengths for audio frequencies. Normally, the wavelength is larger than any of wires used in circuit. Long transmission or power line might be an exception. If the wavelength is much smaller than length of a wire, the basic principles of electronic circuits apply and the principle of electrical circuits is not needed

For wavelength much smaller than length of wire given, the given elements behave as distributed element, so for this condition Maxwell equation is apply

4 0

3 years ago

Java Programming: Loops and Conditionals

velikii [3]

Answer:

import java.util.Scanner;
import java.util.Random;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
Random rand = new Random();
System.out.print("Enter number of questions you wish to practice: ");
int n = input.nextInt();
int i = 1;
while(i <= n){
int num1 = 1 + rand.nextInt(10);
int num2 = 1 + rand.nextInt(10);
int answer = num1 * num2;
System.out.print("Question " + i + ": " + num1 + " x " + num2 + " = ");
int response = input.nextInt();
if(response == answer){
System.out.println("Correct answer!");
}
else{
System.out.println("Wrong answer. It should be " + answer);
}
i++;
}
}
}

Explanation:

Firstly, we import Scanner and Random classes (Line 1-2) as we need to get user input for number of questions and generate random number in each question.

Next, create a Scanner and Random object (Line 7-8). Prompt user to input number of question and get the input using the Scanner object (Line 10-11).

Next create a while loop and set the condition to loop for n number of times (based on number of questions) (Line 14). In the loop, use Random object nextInt method to generate two integers between 1 -10 (Line 15-16). Prompt user to input an answer using the Scanner object (Line 18-19). If the response is matched with answer print a correct message (Line 21-22) other wise inform user they write a wrong answer and show the correct answer (Line 24-25).

8 0

4 years ago

The wall of drying oven is constructed by sandwiching insulation material of thermal conductivity k = 0.05 W/m°K between thin me

masha68 [24]

Answer:

86 mm

Explanation:

From the attached thermal circuit diagram, equation for i-nodes will be

$\frac {T_ \infty, i-T_{i}}{ R^{"}_{cv, i}} + \frac {T_{o}-T_{i}}{ R^{"}_{cd}} + q_{rad} = 0$ Equation 1

Similarly, the equation for outer node “o” will be

$\frac {T_{ i}-T_{o}}{ R^{"}_{cd}} + \frac {T_{\infty, o} -T_{o}}{ R^{"}_{cv, o}} = 0$ Equation 2

The conventive thermal resistance in i-node will be

$R^{"}_{cv, i}= \frac {1}{h_{i}}= \frac {1}{30}= 0.033 m^{2}K/w$ Equation 3

The conventive hermal resistance per unit area is

$R^{"}_{cv, o}= \frac {1}{h_{o}}= \frac {1}{10}= 0.100 m^{2}K/w$ Equation 4

The conductive thermal resistance per unit area is

$R^{"}_{cd}= \frac {L}{K}= \frac {L}{0.05} m^{2}K/w$ Equation 5

Since $q_{rad}$ is given as 100, $T_{o}$ is 40 $T_ \infty$ is 300 $T_{\infty, o}$ is 25

Substituting the values in equations 3,4 and 5 into equations 1 and 2 we obtain

$\frac {300-T_{i}}{0.033} +\frac {40-T_{i}}{L/0.05} +100=0$ Equation 6

$\frac {T_{ i}-40}{L/0.05}+ \frac {25-40}{0.100}=0$

$T_{i}-40= \frac {L}{0.05}*150$

$T_{i}-40=3000L$

$T_{i}=3000L+40$ Equation 7

From equation 6 we can substitute wherever there’s $T_{i}$ with 3000L+40 as seen in equation 7 hence we obtain

$\frac {300- (3000L+40)}{0.033} + \frac {40- (3000L+40)}{L/0.05}+100=0$

The above can be simplified to be

$\frac {260-3000L}{0.033}+ \frac {(-3000L)}{L/0.05}+100=0$

$\frac {260-3000L}{0.033}=50$

-3000L=1.665-260

$L= \frac {-258.33}{-3000}=0.086*10^{-3}m= 86mm$

Therefore, insulation thickness is 86mm

8 0

3 years ago

LEARNING ACTIVITY SHEET

Nady [450]

Answer:

1. It is used to test/check the continuity of the circuit

a. Ohmmeter

2. Is a physical device used to connect electronic test equipment to a device under test

a. Test probes

3. A device inserted to a convenience outlet to conduct electric current

a. Plug

4. Is a stranded wire used to temporary wiring installation and commonly used in extension cord assembly

a. Duplex cord

5. It is a pocket size tool used to test the line wire or circuit if there is a current in it.

a. Test light

6. An instrument used to measure the amount of electrical current intensity in a circuit

b. Ammeter

7. A pocket sized tool used to test the line wire or circuit if there is current in it.

a. Test light

8. A measuring tool used to measure the length of an object in centimeter in it

b) Ruler

9. It is used to measure the diameter of wires/conductors in circular mills. It can measure small and big sizes of wires

a. Micrometer

10. It is used to measure the voltage, resistance and current of a circuit. It is connected in parallel or series with the circuit depending on what to measure

a) Volt-Ohm-milliammeter

11. It is the measuring tool used to measure length, width and thickness of short object and in sketching straight line

Foot rule/ ruler

Explanation:

1. An Ohmmeter tests resistance of a circuit and therefore, indicates if the circuit has continuity (connectivity) by measuring the resistance to the current it sends through the circuit, while the circuit power is switched off

2. A test probe connects a testing equipment to a Device Under Test (DUT)

3. A plug is used to connect an electric appliance to the mains power supply by fitting it into the mains power outlet

4. A duplex cord is used for temporary wiring to supply power in an extension cord assembly

5. A test light is used to determine if a circuit has electric current flowing in it

6. An ammeter measures the amount of direct or alternating current flowing in a circuit

7. Test light is used to check the presence of an electric current in a circuit

8. A ruler is used to measure length and it is marked in cm or in

9. A micrometer measures the diameter of wires placed in between the anvil and spindle

10. A Volt-Ohm-Milliammeter (VOM), is also known as a multimeter that measures voltage, current, and resistance of a circuit

11. A foot rule/ ruler, measures the dimensions of objects that are flat and short

3 0

3 years ago

As a construction manager, Alex found a major issue with the client's design demands. He found out that the building design was

kipiarov [429]

Answer:

Which human resource skill helped Alex convince the client? its nagotiation

Explanation:

got it right on the test.

6 0

3 years ago