Answer:
warmer air
Explanation:
the particles are more excited which increases the probability that the particles will bump into each other
Answer:
Explanation:
initial velocity u = 32.7 m /s
final velocity v = 50.3 m /s
displacement s = 44500 m
acceleration a = ?
v² = u² + 2 a s
50.3² = 32.7² + 2 x a x 44500
2530.09 = 1069.29 + 89000a
a .016 m /s²
time taken t = ?
v = u + at
50.3 = 32.7 + .016 t
t = 1100 s
Answer:
the ball's velocity was approximately 0.66 m/s
Explanation:
Recall that we can study the motion of the baseball rolling off the table in vertical component and horizontal component separately.
Since the velocity at which the ball was rolling is entirely in the horizontal direction, it doesn't affect the vertical motion that can therefore be studied as a free fall, where only the constant acceleration of gravity is affecting the vertical movement.
Then, considering that the ball, as it falls covers a vertical distance of 0.7 meters to the ground, we can set the equation of motion for this, and estimate the time the ball was in the air:
0.7 = (1/2) g t^2
solve for t:
t^2 = 1.4 / g
t = 0.3779 sec
which we can round to about 0.38 seconds
No we use this time in the horizontal motion, which is only determined by the ball's initial velocity (vi) as it takes off:
horizontal distance covered = vi * t
0.25 = vi * (0.38)
solve for vi:
vi = 0.25/0.38 m/s
vi = 0.65798 m/s
Then the ball's velocity was approximately 0.66 m/s
Answer:
all above
Explanation:
friction is necessary to live
Answer:
The coefficient of kinetic friction between the sled and the snow is 0.0134
Explanation:
Given that:
M = mass of person = 52 kg
m = mass of sled = 15.2 kg
U = initial velocity of person = 3.63 m/s
u = initial velocity of sled = 0 m/s
After collision, the person and the sled would move with the same velocity V.
a) According to law of momentum conservation:
Total momentum before collision = Total momentum after collision
MU + mu = (M + m)V
![V=\frac{MU+mu}{M+m}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BMU%2Bmu%7D%7BM%2Bm%7D)
Substituting values:
![V=\frac{MU+mu}{M+m}=\frac{52(3.63)+15.2(0)}{52+15.2} =2.81m/s](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BMU%2Bmu%7D%7BM%2Bm%7D%3D%5Cfrac%7B52%283.63%29%2B15.2%280%29%7D%7B52%2B15.2%7D%20%3D2.81m%2Fs)
The velocity of the sled and person as they move away is 2.81 m/s
b) acceleration due to gravity (g) = 9.8 m/s²
d = 30 m
Using the formula:
![V^2=2\mu(gd)\\\mu=\frac{V^2}{2gd} \\\mu=\frac{2.81^2}{2*9.8*30} =0.0134](https://tex.z-dn.net/?f=V%5E2%3D2%5Cmu%28gd%29%5C%5C%5Cmu%3D%5Cfrac%7BV%5E2%7D%7B2gd%7D%20%5C%5C%5Cmu%3D%5Cfrac%7B2.81%5E2%7D%7B2%2A9.8%2A30%7D%20%3D0.0134)
The coefficient of kinetic friction between the sled and the snow is 0.0134