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Slav-nsk [51]
3 years ago
15

IN WHAT WAY HAS TECHNOLOGY USED ABOARD THE INTERNATIONAL SPACE STATION BENEFITTED HUMANS BACK ON EARTH?

Physics
2 answers:
drek231 [11]3 years ago
6 0

Answer

The ways are;

• By commercializing low earth orbit

• By supporting water purification efforts worldwide

• By bringing space station ultrasound equipment on earth

• By improving eye surgery with space hardware

Explanation

There is a revolutionary commercial pathways that is currently opening access to space.For example, NASA is purchasing commercial cargo resupply to space station which enable U.S business to develop a competition in selling services to others while freeing NASA resources for deep space exploration. Using  technology developed in space, the Water Security Corporation has deployed systems using NASA water-processing technology to ensure drinkable water availability for human survival. Medical care in remote regions is now  facilitated by use of small ultrasound units, tele-medicine  and remote guided methods similar to those used in space. The Eye Tracking Device experiment has enable researchers to have an insight into corrective laser surgeries.


Leya [2.2K]3 years ago
4 0

Answer:c

Explanation:

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A bungee jumper who is about to jump has her energy stored entirely as
Morgarella [4.7K]

Answer:

it will get slower and eventually she will stop jumping because there isnt enough force on the gravity causing her to go up and down

Explanation:

!!

3 0
3 years ago
The wheels of a wagon can be approximated as the combination of a thin outer hoop, of radius ????h=0.209 m and mass 4.32 kg , an
Stolb23 [73]

Answer:

r= 98.3 mm

Explanation:

For rim

R= 0.209 m

M= 4.32 kg

For rods

m= 7.37 kg

L= 2 R= 2 x 0.209 = 0.418 m

The Total moment of inertia of the  wagon

I=MR²+2 x 1/12 m L²

Now by putting the values

I=4.32\times 0.209^2+2\times \dfrac{1}{12}\times 7.73\times 0.418^2\ kg.m^2

I=0.413 kg.m²

For disk:

t= 0.0462 m

Density ρ = 5990 kg/m³

Lets take r is the radius of disk

So the mass of the disc

m'=ρ πr² t

The moment of inertia of disc

I'=1/2 m'r²

I'=1/2 x r² x ρ πr² t

Given that

I = I'

1/2 x r² x ρ πr² t = 0.413 kg.m²

1/2 x r³ x ρ π t = 0.413

r³ x ρ π t = 0.826

r^3=\dfrac{0.826}{\pi \times 5990 \times 0.0462}

r³=0.00095

r=0.0983 m

r= 98.3 mm

8 0
3 years ago
A gas is compressed in a cylinder from a volume of 20.0 l to 2.0 l by a constant pressure of 10.0 atm. calculate the amount of w
jok3333 [9.3K]
First, we need to convert the pressure in SI units. Keeping in mind that 1 atm = 1.01 \cdot 10^5 Pa:
p=10.0 atm =1.01 \cdot 10^6 Pa

The initial and final volume of the gas are (keeping in mind that 1.0 L = 0.001 m^3):
V_i = 20.0 L=0.020 m^3
V_f = 2.0 L=0.002 m^3

So, the work done on the gas by the surrounding is
W= -p \Delta V=-p(V_f-V_i)=-(1.01 \cdot 10^6 Pa)(0.002 m^3-0.020 m^3)=18180 J
And the final positive sign means that this work corresponds to an increase in internal energy of the gas.
8 0
3 years ago
What is the net charge of a metal ball if there are 21,749 extra electrons in it?
pickupchik [31]

Answer:

Q=3.47\times 10^{-15}\ C

Explanation:

Given that,

Number of extra electrons, n = 21749

We need to find the net charge on the metal ball. Let Q is the net charge.

We know that the charge on an electron is q=1.6\times 10^{-19}\ C

To find the net charge if there are n number of extra electrons is :

Q = n × q

Q=21749\times 1.6\times 10^{-19}\ C

Q=3.47\times 10^{-15}\ C

So, the net charge on the metal ball is 3.47\times 10^{-15}\ C. Hence, this is the required solution.

6 0
3 years ago
. A student thinks that the more protons an atom has, the more reactive it will be. Which will best disprove this student's idea
shepuryov [24]
The best answer to the question that is being stated above would be the first choice. To disprove the claims of the student that you need more protons to have more reactivity, then you proceed to compare the reactivities of lithium (Li) and krypton (Kr). Krypton has more protons than Lithium, but it is less reactive because it is a noble gas.
6 0
3 years ago
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