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Slav-nsk [51]
3 years ago
15

IN WHAT WAY HAS TECHNOLOGY USED ABOARD THE INTERNATIONAL SPACE STATION BENEFITTED HUMANS BACK ON EARTH?

Physics
2 answers:
drek231 [11]3 years ago
6 0

Answer

The ways are;

• By commercializing low earth orbit

• By supporting water purification efforts worldwide

• By bringing space station ultrasound equipment on earth

• By improving eye surgery with space hardware

Explanation

There is a revolutionary commercial pathways that is currently opening access to space.For example, NASA is purchasing commercial cargo resupply to space station which enable U.S business to develop a competition in selling services to others while freeing NASA resources for deep space exploration. Using  technology developed in space, the Water Security Corporation has deployed systems using NASA water-processing technology to ensure drinkable water availability for human survival. Medical care in remote regions is now  facilitated by use of small ultrasound units, tele-medicine  and remote guided methods similar to those used in space. The Eye Tracking Device experiment has enable researchers to have an insight into corrective laser surgeries.


Leya [2.2K]3 years ago
4 0

Answer:c

Explanation:

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A massless, hollow sphere of radius R is entirely filled with a fluid such that its density is p. This same hollow sphere is now
Vesnalui [34]

Answer:

a. 8p

Explanation:

We are given that

Radius of hollow sphere , R1=R

Density of hollow sphere=\rho

After compress

Radius of hollow sphere, R2=R/2

We have to find density of the compressed sphere.

We know that

Density=\frac{mass}{volume}

Mass=Density\times volume=Constant

Therefore,\rho_1 V_1=\rho_2V_2

Volume of sphere=\frac{4}{3}\pi r^3

Using the formula

\rho\times \frac{4}{3}\pi R^3=\rho_2\times \frac{4}{3}\pi (R/2)^3

\rho R^3=\rho_2\times \frac{R^3}{8}

\rho_2=8\rho

Hence, the density of  the compressed sphere=8\rho

Option a is correct.

7 0
3 years ago
A tennis ball with a speed of 25.9 m/s is moving perpendicular to a wall. After striking the wall,
mihalych1998 [28]

Answer:

-3550.1 m/s^2

Explanation:

The initial velocity of the ball is

u = +25.9 m/s (towards the wall)

while the final velocity of the ball is

v = -21.3157 m/s (away from the wall)

The time taken for the change in velocity to occur is

t = 0.0133 s

The acceleration can be calculated as the  change in velocity divided by the time taken:

a=\frac{v-u}{t}

Substituting the numbers, we find:

a=\frac{-21.3157-25.9}{0.0133}=-3550.1 m/s^2

6 0
3 years ago
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storchak [24]

Answer

given,

wavelength = λ = 18.7 cm

                    = 0.187 m

amplitude , A = 2.34 cm

v = 0.38 m/s

A)  angular frequency = ?

     f = \dfrac{v}{\lambda}

     f = \dfrac{0.38}{0.187}

     f =2.03\ Hz

angular frequency ,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) the wave number ,

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     K= \dfrac{2\pi}{0.187}

    K =33.59\ m^{-1}

C)

as the wave is propagating in -x direction, the sign is positive between x and t

y ( x ,t) = A sin(k  x - ω t)

y ( x ,t) = 2.34  x  sin(33.59 x - 12.75 t)

4 0
3 years ago
A cobalt atom contains 27 protons, 32 neutrons, and 27 electrons. What is
kirza4 [7]
32? I could be wrong but I’m going with that answer choice
3 0
2 years ago
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Romashka-Z-Leto [24]

, density is how compact an object is. Put another way, density is the mass of an object divided by its volume.

5 0
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