Answer:
No, This is not a valid Probability Distribution
Step-by-step explanation:
Probability [Neighbour walks with Beagle] = 20%
Probability [Neighbour walks with Golden Retriever] = 70%
Probability [Neighbour walks alone] = 30%
Disjoint Events are the events that have zero probability of occurring together. If all the three above items are disjoint, it means that it can never happen that two of them happen together.
The total (summed) probability of a valid probability distribution, with disjoint sets = 1 . In given case, total probability = 0.2 + 0.7 + 0.3 = 1.2 ; i.e > 1.
So, this probability distribution with stated disjoint events is not a Valid Probability distribution.
Answer:
cant really see it
Step-by-step explanation:
Answer:
7/6 or 1.166666667
Step-by-step explanation:
I solved it on calculator
To 1 d.p 1.2
Answer:
3 units right and 1 unit up.
Simplify <span>22\times 2<span>22×2</span></span> to <span>44<span>44</span></span>
<span><span>{x}^{4}+44-16x-12<span><span>x<span><span>4</span><span></span></span></span>+44−16x−12</span></span>Collect like terms
<span><span>{x}^{4}+(44-12)-16x<span><span>x<span><span>4</span><span></span></span></span>+(44−12)−16x</span></span> Simplify</span><span><span>{x}^{4}+32-16x<span><span>x<span><span>4</span><span></span></span></span>+32−16x</span></span><span>
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