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AlexFokin [52]
3 years ago
5

How does a balanced equation show the conversation of mass

Chemistry
1 answer:
Elza [17]3 years ago
5 0
Balanced chemical equations show that mass is conserved in chemical reactions.
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marissa [1.9K]

Answer:

Filtration is the best method or seiving to put the drink in a cup while the seed falls on the seiver

Explanation:

6 0
3 years ago
How many atoms are in 1.4 moles of H3PO4?
sdas [7]
<h3>Answer:</h3>

8.4 × 10²³ atoms H₃PO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.4 moles H₃PO₄

[Solve] atoms H₃PO₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.4 \ mol \ H_3PO_4(\frac{6.022 \cdot 10^{23} \ atoms \ H_3PO_4}{1 \ mol \ H_3PO_4})
  2. [DA] Multiply [Cancel out units]:                                                                    \displaystyle 8.4308 \cdot 10^{23} \ atoms \ H_3PO_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

8.4308 × 10²³ atoms H₃PO₄ ≈ 8.4 × 10²³ atoms H₃PO₄

3 0
3 years ago
How many significant figures does 0.0006510 of have?
arsen [322]
It has 4 significant figures. If you see the Zero after the one decimal point you don’t count that and instead just started at 6
7 0
4 years ago
Read 2 more answers
I will give Brainliest!!! What kind of atoms makeup C12H22O11?
Goshia [24]

Answer:

carbon, hydrogen, and oxygen atoms

Explanation:

brainliest pls

7 0
2 years ago
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According to Le Châtelier's principle, how will an increase in concentration of a reactant affect the equilibrium system?
Svetach [21]

Answer:

Shift it toward the products

Explanation:

Imagine this equilibrium:

2A  +  B   ⇄  A₂B

Let's think the expression for Kc:

Kc = [A₂B] / [A]² . [B]

Now, we have this situation:

2A ↑  +  B   ⇄  A₂B

As we are not in equilibrium, we have to think that Kc would decrease.

↓Kc = [A₂B] / [A]² ↑ . [B]

so we have to use Qc (reaction quotient). For this case

Qc < Kc, so the reaction → Product side

We have to make more product to counteract the reagent increase and thus return the system to equilibriumr

3 0
3 years ago
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