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3 years ago

How does a balanced equation show the conversation of mass

Chemistry

1 answer:

Elza [17]3 years ago

5 0

Balanced chemical equations show that mass is conserved in chemical reactions.

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*10 points* PLS HELP!!!!!!!!!!!!!!!!

CaHeK987 [17]

Aluminum foil I think but if not goodluck :)

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2 years ago

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What type of minerals are these??

skelet666 [1.2K]

Answer:

talc mineral and magnetite

Explanation:

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2 years ago

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The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C

Kay [80]

Answer: The percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope be 'x'. So, fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope will be '1 - x'

For $_{17}^{35}\textrm{Cl}$ isotope:

Mass of $_{17}^{35}\textrm{Cl}$ isotope = 35 amu

Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

For $_{17}^{37}\textrm{Cl}$ isotope:

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 37 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

$35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775$

Percentage abundance of $_{17}^{35}\textrm{Cl}$ isotope = $0.775\times 100=77.5\%$

Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.775)=0.225\times 100=22.5\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

6 0

3 years ago

Make a good chain with arrows include these organisms white shark,bacteria,kelp,sun,sea urchin,otter

MakcuM [25]

Sun to kelp

kelp to sea urchin

sea urchin to otter

otter to shark

kelp,sea urchin,otter,shark to bacteria

bacteria back to kelp

8 0

2 years ago

Lastly, Snape thinks we should try one more calculation.

EleoNora [17]

Answer:

E) 0.90

Explanation:

In TLC (Thin-Layer-Chromatography) retention factor RF is defined as the ratio between distance of the sample and the solvent front. RF is very important in chemistry to know the composition of any sample by comparison.

In the problem, as the sample has a distance of 0,20cm from the solvent front, the distance of the sample is:

2,0cm - 0,20 cm = 1,8 cm. Thus, RF is:

RF = 1,8cm / 2,0cm = 0,90

E) 0,90

I hope it helps!

3 0

2 years ago