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AlexFokin [52]
3 years ago
5

How does a balanced equation show the conversation of mass

Chemistry
1 answer:
Elza [17]3 years ago
5 0
Balanced chemical equations show that mass is conserved in chemical reactions.
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What is the final temperature of a 34.2 g of water initially at 282 K that has been heated with 2.71 kJ of energy?
lana66690 [7]

Answer: The final temperature of copper is  

Further explanation:

The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:

1. Intensive properties:

These are the properties that depend on the nature of the substance. These don't depend on the size of the system. Their values remain unaltered even if the system is further divided into a number of subsystems. Temperature, refractive index, concentration, pressure, and density are some of the examples of intensive properties.

2. Extensive properties:

These are the properties that depend on the amount of the substance. These are additive in nature when a single system is divided into many subsystems. Mass, enthalpy, volume, energy, size, weight, and length are some of the examples of extensive properties.

Specific heat is the amount of heat required to increase the temperature of any substance per unit mass. Specific heat capacity is also known as mass specific heat. Its SI unit is Joule (J).

The formula to calculate the heat energy of copper is as follows:

                                       …… (1)

Here,

Q is the amount of heat transferred.

m is the mass of copper.

c is the specific heat of copper.

is the change in temperature of copper.

Rearrange equation (1) to calculate the temperature change.

                                   …… (2)

The value of Q needs to be converted into J. The conversion factor for this is,

So the value of Q can b calculated as follows:

The value of Q is 4689 J.

The value of m is 34.2 g.

The value of c is .

Substitute these values in equation (2).

The temperature change  can be calculated as follows:

                         …… (3)

Here,

is the change in temperature.

is the final temperature.

is the initial temperature.

Rearrange equation (3) to calculate the final temperature.

                      …… (4)

The value of  is .

The value of  is  

Substitute these values in equation (4).

So the final temperature of copper is .

7 0
3 years ago
Describe the term molarity as it relates to an acid or base.
Sidana [21]
Molarity is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. Acids and bases can be measured through the concentrations of H+ and OH- ions in units of molarity. Hope this helps.
4 0
4 years ago
Read 2 more answers
In the process of eukaryotic pre-mRNA splicing, how is the lariat intermediate formed?
Aleks [24]

Answer:

C

Explanation:

The Eukaryotic pre-mRNA receives a 5' cap and 3'poly(A) tail before Introns are removed and the mRNA is considered ready for translation.

4 0
3 years ago
Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
Anna11 [10]

Answer:

[COF₂] = 0.346M

Explanation:

For the reaction:

2COF₂(g) ⇌ CO₂(g) + CF₄(g)

Kc = 5.70 is defined as:

Kc = [CO₂] [CF₄] / [COF₂]² = 5.70 <em>(1)</em>

Equilibrium concentrations of each compound after addition of 2.00M COF₂ will be:

[COF₂] : 2.00M - 2x

[CO₂] : x

[CF₄] : x

Replacing in (1):

5.70 =  [X] [X] / [2-2x]²

22.8 - 45.6x + 22.8x² = x²

0 = -21.8x² + 45.6x - 22.8

Solving for x:

X = 1.265 <em>-False answer, will produce negative concentrations-</em>

<em>X = 0.827.</em>

Replaing, molar concentration of COF₂ is:

[COF₂] : 2.00M - 2×0.827 = <em>0.346M</em>

I hope it helps!

7 0
3 years ago
I NEED HELP ASAPPP!! I WILL GIVE YOU A GOOD RATING LOL
ruslelena [56]

Answer:

Yes N3- is correct ion notation. The N element is in the form N2 . Also it is a triple covalent bond and so this correct

3 0
3 years ago
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